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FN: 76
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- Consider the bracket shown in Fig-1. If: F1 = 10 N@ 120° • F2 = 75 N@ -90° then, what is the magnitude of the resultant force on the bracket? 8.66 N 66.5 N -75 N 75 N O ON 66.3 N*m 100 N*m O 10 NThe following diagram corresponds to questions 1 to 3. A beam rests on two sharp edges as shown on the image. The beam has a length of 7,50 m and a mass of 4,25 kg. Object 1 has a mass of 1,50 kg; object 2 has a mass of 2,35 kg. Point P is 0,50 m form the center of the beam. d 2 Pl CG 1. How much is the torque done by object 1 around point P? A. 55,2 N*m B. 7,36 N*m С. 62,5 N*m D. Object 1 doesn't exert a torque./Find the two forces Fbc & Fac as shown :in the figure below Fab=30 N Fbc 50 30 Fac (Fbc=55 N and Fac= 70 N) O (Fbc=40 N and Fac= 50 N) O (Fbc=46 N and Fac= 59 N) O
- 1. A 100lb weight is suspended by three cables as shown in the figure. The ratios of the stiffness of the cables are: AP:BP:CP = 2k:k:3k, i.e. cable AP and CP are respectively 2x and 3x the stiffness of cable BP. Before the load is applied, all three cables are unloaded and the geometry is as shown. B 45° 60⁰ V 60" P you 45° C 461 Assuming the cables are very stiff and the displacements are therefore small, determine the forces in the three cables in terms of stiffness value k and the weight W(= 100). Assuming the springs are not stiff, and therefore the displacements are not necessarily small, develop a set of equations for the displacement of the mass and the forces in the cables.Figure Q2 (a) shows a bar that loaded as below. Given: F1=11 N, F2=23 N and e= 30°. (Please provide answer in newton, N with two decimal places). 6m 1.5 m 40° F2m - Figure Q2 (a) Determine the total magnitude of force, EFx acting in x-direction. (answer in newton, N with a single decimal place)Consider the bracket shown in Fig-3. If: • F1 = 10 lb @ -90° • a - 2 ft • b = 4 ft • c= 1 ft then, what is the magnitude of the internal force within member 'BD'? O lb 10 lb 14.2 Ib 20 lb 26.4 lb 30 lb 32.3 lb 40 Ib 45 lb 50 Ib 54.1 Ib 60 Ib 67.1 lb 70 lb 72.7 lb
- OP •C h W The man in the diagram is trying to move a large box by pushing on it with a force, P. The box weighs 300 N and its centre of gravity is located in the centre of the box (point C). Given: a = 1.8 m b = 0.8 m h= 0.9 m What is the minimum force that will cause the box to tip? Please include the unit ("N") within your answer and round to 3 significant figures (e.g. if the calculated answer was 55.562 Newtons please input: 55.6 N). Answer: What is the minimum coefficient of static friction that will permit tipping to occur? Please do not include the unit s (as there are none) within your answer and round to 3 significant figures (e.g. if the calculated answer was 55.562 please input: 55.6). Answer:Consider the bracket shown in Fig-1. If: F1 = 10 N@ 120° • F2 = 75 N@ -90° then, what is the direction of the resultant force on the bracket? 176° 4.31° -4.31° 2.17° -176° -2.17° 94.3° -94.3°Given values: m1 = 10kg, r1=75 cm, m3=20kg, r3=25cm, m4=5kg, had to find the value of r4=? I got r4=50cm m1 = 10 kg at r1 = 75cm m3 = 20 kg at r3 = 25cm m4 = 5 kg at r4 = 50cm 1. Compute the theoretical value of r3 using the following equation: r1m1 = r3m3 + r4m4 2. Compute the % error of r3 using the following equation: % error = |theoretical value - experimental value| / theoretical value x 100%
- A sandwich board advertising sign is constructed as shown in the figure below. Hinge- Chain G2001 Brooks/Cole Thomson Learning CG CG 0.50 m Uniform board (CG at center) 1.10 m 1.30m The sign's mass is 5.30 kg. (a) Calculate the tension in newtons in the chain assuming no friction between the legs and the sidewalk. XN (b) What force is exerted in newtons by each side on the hinge? X NThe following diagram corresponds to questions 1 to 3. A beam rests on two sharp edges as shown on the image. The beam has a length of 7,50 m and a mass of 4,25 kg. Object 1 has a mass of 1,50 kg; object 2 has a mass of 2,35 kg. Point P is 0,50 m form the center of the beam. CG 1. How much is the torque done by object 1 around point P? A. 55,2 N*m B. 7,36 N*m C. 62,5 N*m D. Object 1 doesn't exert a torque. 2. How much is the torque done by the force of gravity of the beam around point P? A. 20,8 N*m N-m ך177 .B C. 156 N*m D. 313 N*m 3. If you needed to cancel the nomal forces of the two objects, where you should place object 2? The axis of rotation is point P. A. 3,30 m from point B. 9,18 m from point P C. 5,69 m from point P D. 3,62 m from point P3. A mobile is constructed of light rods, light strings, and beach souvenirs as shown in the figure below. If m4 = 12.0 g, find values (in g) for the following. (Let d1 = 4.50 cm, d2 = 6.10 cm, d3 = 2.40 cm, d4 = 4.40 cm, d5 = 2.90 cm, and d6 = 3.50 cm.) 4. One end of a uniform 3.70-m-long rod of weight Fg is supported by a cable at an angle of ? = 37° with the rod. The other end rests against the wall, where it is held by friction as shown in the figure below. The coefficient of static friction between the wall and the rod is μs = 0.495. Determine the minimum distance x from point A at which an additional object, also with the same weight Fg, can be hung without causing the rod to slip at point A.