Consider the bracket shown in Fig-3. If: • F1 = 10 lb @ -90° • a = 2 ft • b= 4 ft c= 1 ft then, what is the magnitude of the internal force within member 'BD?
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- A cargo ship is tied down to marine boll arts at a number of points along its length while its cargo is unloaded by a container handling crane. Each bollard is fastened to the wharf using anchor bolts. Three cables having known tension force magnitudes F, = ll0 kN.F, = 85kN.and F, 9OkNare secured to one bollard at a point A with coordinates (0.0.45 m. 0) in the x-r-: coordinate system shown in the figure part b. Each cable force is directed at an attachment point on the ship. Force F, is directed from point A to a point on the ship having coordinates (3 m, 9 m. 0) force F, is directed at a point with coordinates (6.5 m. 8.5 m. 2 m) and force F, is directed at a point with coordinates (8 m. 9 m. S m). The diameter of each anchor bolts is 4 24 mm. (a) Find the reaction forces and reaction moments at the base of the bollard. (b) Calculate the average shear stress in the anchor bolts (in the x-: plane). Assume each bolt cart ics an equal share of the total force.Two steel wines support a moveable overhead camera weighing W = 28 lb (see figure part a) used For close-up to viewing of field action at sporting, events. At some instant, wire I is at an angle a = 22° to the horizontal and wire 2 is at angle fi = 40°. Wires I and 2 have diameters of 30and 35 mils, respectively. (Wire diameters are often expressed in mils; one mil equals 0.001 in.) (a) Determine the tensile stresses s and s2 in the two wires. (b) If the stresses in wires 1 and 2 must be the same, what is the required diameter of wire 1 ? (c) To stabilize the camera for windy outdoor conditions, a third wire is added (see figure part b). Assume the three wires meet at a common point coordinates (0, 0. 0) above the camera at the instant shown in figure part b. Wire I is attached to a support at coordinates (75 ft, 48 ft, 70 Ft). Wire 2 is supported at (-70 ft. 55 ft, 80 Ft). Wire 3 is supported at (-10 ft. -85 Ft, 75 ft). Assume that all three wires have a diameter of 30 mils. Find the tensile stresses in all three wiresENTER YOUR ANSWER THE WAY I SPECIFY HERE IN ADDITION TO DOING IT ON SCRATCH PAPER 400 N 800 N B D A E C 2 m Use the method of sections to calculate the axial force in members AC and BC. Enter your answer in the following way rounded to the nearest whole number. Example If your answer is TAC 2 N tension TBC =3.1 N compression. enter 2Tension;3Compression Enter TAC then TBC (no space)
- Two concentric springs of equal lengths are placed in an assembly shown below. A force P is applied against the plate above. Select all equations among the choices that hold true. No partial points. Note: P is force, ō is change in length. Pouter + Pinner = P Pouter = Pinner = P Souter = dinner douter #dinner P -WwwandConsider the bracket shown in Fig-3. If: F1 = 10 lb @ -90° • a - 2 ft • b = 4 ft • c= 1 ft then, what is the type of the internal force within member 'BD'? compressive tensileA round steel bar with a diameter of 1.500 in is subjected to the axial loads shown. P1 = 95 k, P2 = 115 k, P3= 55 k, P4 = (P1-P2+P3) k. If Section 2 has a length, L2 = 65 inches, find the change in length of Section 2. Report the answer below in inches, absolute value, 3 significant digits. P1 Your Answer: 100 inches Round Steel Bar P2 Section 2 12 P3 80 inches P4
- The figure shows a rigid bar that is supported by a pin at A and two rods, one made of steel and the other of bronze. Neglecting the weight of the bar, compute the force (in N) in the bronze rod caused by the 42563-Nload, using the following data: length of steel = 1.56 m, length of bronze = 2.18 m Area of steel = 563 mm, Area of bronze = 233 mm Modulus of elasticity of steel = 193 Gpa, Modulus of elasticity of bronze = 82 Gpa x = 0.69 m, y = 1.03 m, and z = 0.79 m.The figure shows a rigid bar that is supported by a pin at A and two rods, one made of steel and the other of bronze. Neglecting the weight of the bar, compute the force (in N) in the bronze rod caused by the 48512-Nload, using the following data: length of steel = 1.42 m, length of bronze = 2.36 m Area of steel = 639 mm, Area of bronze = 319 mm Modulus of elasticity of steel = 180 Gpa, Modulus of elasticity of bronze = 81 Gpa x = 0.58 m, y = 1.13 m, and z = 0.72 m. Round off the final answer to two decimal places.The figure shows a rigid bar that is supported by a pin at A and two rods, one made of steel and the other of bronze. Neglecting the weight of the bar, compute the force (in N) in the steel rod caused by the 43091-Nload, using the following data: length of steel = 1.36 m, length of bronze = 2.08 m Area of steel = 562 mm, Area of bronze = 243 mm Modulus of elasticity of steel = 215 Gpa, Modulus of elasticity of bronze = 102 Gpa x = 0.63 m, y = 1.01 m, and z = 0.84 m.
- Given values: m1 = 10kg, r1=75 cm, m3=20kg, r3=25cm, m4=5kg, had to find the value of r4=? I got r4=50cm m1 = 10 kg at r1 = 75cm m3 = 20 kg at r3 = 25cm m4 = 5 kg at r4 = 50cm 1. Compute the theoretical value of r3 using the following equation: r1m1 = r3m3 + r4m4 2. Compute the % error of r3 using the following equation: % error = |theoretical value - experimental value| / theoretical value x 100%The figure shows a rigid bar that is supported by a pin at A and two rods, one made of steel and the other of bronze. Neglecting the weight of the bar, compute the force (in N) in the steel rod caused by the 42758-Nload, using the following data: length of steel = 1.27 m, length of bronze = 2.06 m Area of steel = 522 mm, Area of bronze = 239 mm Modulus of elasticity of steel = 216 Gpa, Modulus of elasticity of bronze = 84 Gpa x= 0.69 m, y = 1.08 m, and z = 0.86 m. Round off the final answer to three decimal places. ... Bronze Steel Ey te zQ1: 30-mm-diameter steel bar is to be used as a torsion spring. If the torsional stress in the bar is not to exceed 110 MPa when one end is twisted through an angle of 30°, what must be the length of the bar in m? modulus of rigidity=80 GPa . (close to two decimal)