78 At time t = 0, a 12.0 V potential difference is suddenly applied to the leads of a coil of inductance 23.0 mH and a certain resistance R. At time t = 0.150 ms, the current through the induc- tor is changing at the rate of 280 A/s. Evaluate R.

In an RC series circuit, ℰ = 15.0 V, R = 2.00 MΩ, and C = 1.80 μF. (a) Calculate the time constant. _____________s(b) Find the maximum charge that will appear on the capacitor during charging. ___________μC(c) How long does it take for the charge to build up to 12.0 μC? ___________s (please show the units when working through the problem so that I can follow it easier)

When switch S in (Figure 1) is open, the voltmeter V of the battery reads 3.13 V. When the switch is closed, the voltmeter reading drops to 2.93 V, and the ammeter A reads 1.69 A. Assume that the two meters are ideal, so they don't affect the circuit. For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of A source with a short circuit. Figure S V r E -ww+ R A 1 of 1 Find the emf. Express your answer in volts. E = Submit Part B r = Find the internal resistance r of the battery. Express your answer in ohms. Submit Part C Π| ΑΣΦ Request Answer R= | ΑΣΦ Request Answer Find the resis ance R. Express your answer in ohms. IVE| ΑΣΦ ? ? ? V Ω Ω

An ECG monitor must have an RC time constant less than 1.00 × 102 μs so it can measure variations in voltage over small time intervals. If the resistance of the circuit (due mostly to that of the patient’s chest) is 0.85 kΩ, what is the maximum capacitance of the circuit in F?

Consider an initially uncharged capacitor in an RC circuit. The resistance is 25,957 Ohms and the capacitance is 555 x 10^-6 F. If the source potential being used to charge the capacitor is 14.8 V, how long after charging begins will the energy stored by the capacitor be 65.5% of its maximum value.

A discharging RC circuit has its charge reduced from 20C to 10C in 22 seconds. If the resistance of the circuit is 11 Ohms then what is the capacitance?