College Physics
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An RC circuit takes t = 1.58 s to charge to 45% when a voltage of ΔV = 5.5 V is applied.
What is this circuit's time constant τ, in seconds?
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- Consider an initially uncharged capacitor in an RC circuit. The resistance is 25,957 Ohms and the capacitance is 555 x 10^-6 F. If the source potential being used to charge the capacitor is 14.8 V, how long after charging begins will the energy stored by the capacitor be 65.5% of its maximum value.arrow_forwardThe RC circuit shown in (Figure 1) can be used in an artificial pacemaker to establish a normal heart rhythm by generating periodic electrical impulses. The box labeled "controller" behaves as an open circuit until the voltage drop across the capacitor reaches a preset limit. Once that limit is reached, the capacitor discharges its stored energy in the form of an electrical impulse to the heart, starts to recharge, and then the process repeats. Figure + Vs R m C + VC Part A Calculate the heart rate in beats per minute for R = 200 kn and C = 5.0 μF, if the capacitor discharges when its voltage reaches 80% of the source voltage Vs. Express your answer in beats per minute to three significant figures. H = Submit 17 ΑΣΦ V ↓↑ Request Answer < Return to Assignment vec Provide Feedback ? beats per minutearrow_forwardIn the circuit shown in the figure, the S switch closed at t=0 and the capacitors, which are completely empty, begin to fill. Here ε=10 V, C=5 μF and R=55 Ω. What is the time constant of the circuit, τ, in units of microseconds? When t= τ, what is the total charge, in units of microcoulomb, accumulated in the capacitors?arrow_forward
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