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7. Use a Punnett square to explain why a cross between two heterozygous individuals will result in offspring that exhibit both the dominant and recessive phenotypes.

Biology: The Dynamic Science (MindTap Course List)

4th Edition

ISBN:9781305389892

Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Publisher:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Chapter12: Mendel, Genes, And Inheritance

Section12.1: The Beginnings Of Genetics: Mendel’s Garden Peas

Problem 1SB: Two pairs of traits are segregating in a cross. Two parents produce 156 progeny that fall into 4...

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Concept explainers

Inheritance and Mendelian Genetics

Inheritance means the passing of traits to offspring from parents. These traits could be passed either through asexual reproduction or sexual reproduction. The offspring receives the genetic material from the parents. Mendelian inheritance is a certain biological inheritance that follows the rules and principles laid down by Gregor Mendel in 1865. The initial hypothesis was considered wrong, but other inheritance theories modified the concept of inheritance and thus genetics.

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7. Use a Punnett square to explain why a cross between two heterozygous individuals will result in
offspring that exhibit both the dominant and recessive phenotypes.

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3. In seals, the gene for the length of the whiskers has two alleles. The dominant allele (W) codes long whiskers and the recessive allele (w) codes for short whiskers. What is the probability of producing offspring that have short whiskers from a cross of two long-whiskered seals, one that is homozygous dominant and one that is heterozygous? Genotype: Phenotype:
7. In pea plants, the dominant allele for flower color is yellow (Y), and the recessive allele is white (y). If a homozygous dominant (YY) yellow-flowered plant is crossed with a heterozygous (Yy) yellow flowered plant what will be the possible genotypes and phenotypes of the offspring? Possible genotypes: Possible phenotypes:
1. How many different types of gametes can be produced by an individual with the genotype Yy Ww Pp ee Bb? 2. If an individual with the genotype Yy Ww Pp ee Bb is crossed with another individual with the same genotype, what proportion of offspring will be homozygous recessive at all genes? 3. If an individual with genotype Yy Ww Pp ee Bb is crossed with an individual with the same genotype, what proportion of offspring will have the dominant phenotype for the four heterozygous loci?
10. In the video example, the sex-linked disorder was a recessive trait. However, sex-linked disorders can be dominant! (Conduct a search to see some of the sex-linked dominant disorders that exist). Sex- linked dominant disorders will show even if there is only one dominant allele present. Using the allele D to stand for a dominant sex-linked trait, show a cross with a woman who does not have a dominant sex-linked disorder (X*Xª) with a man that does. Will the disorder in this particular cross be more common in daughters or sons?
Punnett Square Worksheet Black is the dominant fur color for rabbits and white is the recessive. B stands for the black allele and b represents the white allele. A white rabbit would have a genotype of bb and a black rabbit could have a genotype of BB or Bb. 1. Fill in the missing information for each Punnette square below: Cross 1 Cross 2 Cross 3 в B b B B Cross 4 Cross 5 Cross 6 B b b b B b B Cross 7 Cross 8 Cross 9 b Bb Bb BB Bb b Bb Bb BB Bb 2. List the probability of having black fur for each cross Cross 1: Cross 2: Cross 3: Cross 4: Cross 5: Cross 6: Cross 7: Cross 8: Cross 9: B.
6. Cross a Heterozygous Green Parakeet with a white Parakeet. What is the percentage of the genotype and phenotype of the offspring? What type of punnett square will you be using for this cross? Parents: Genotypes: P1 x P2 Offspring: Genotype: Phenotype:
5. Cross a Hooked Nose-tail bearing Hobbit with a heterozygous straight nosed none-tail bearing hobbit. What is the percentage of the genotype and phenotype of the offspring? What type of punnett square will you be using for this cross? Parents: Genotypes: P1 x P2 Offspring: Genotype: Phenotype:
3. Set up a Punnett square using the following information: Dominate allele for purple corn kernels = R Recessive allele for yellow corn kernels =r Dominate allele for starchy kernels = T Recessive allele for sweet kernals =t Cross a homozygous dominant parent with a heterozygous parent. Using the Punnett square above: a. What is the probability of producing purple, starchy corn kernels? Possible genotype(s)? b. What is the probability of producing yellow, starchy corn kernels? Possible genotype(s)? c.What is the probability of producing purple, sweet corn kernels? Possible genotype(s)? d. What is the probability of producing yellow, sweet corn kernels? Possible genotype(s)?
2. Show the cross and provide full justification in each case: a) An F1 x F1 self-fertilization gives a 9:7 phenotypic ratio in the F2. What phenotypic ratio would you expect if you test-crossed the F1? b) An F1 x F1 self-fertilization gives a 9:3:4 phenotypic ratio in the F2. What phenotypic ratio would you expect if you test-crossed the F1? c) An F1 x F1 self-fertilization gives a 15:1 phenotypic ratio in the F2. What phenotypic ratio would you expect if you test-crossed the F1?
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1. In fruit flies, the phenotype for eye color is determined by a certain locus. E indicates the dominant allele and eindicates the recessive allele. The cross between a male wild-type fruit fly and a female white-eyed fruit flyproduced the following offspring.Wild-typeMaleWild-typeFemaleWhite-eyedMaleWhite-eyedFemaleBrown-eyedFemaleF1 0 45 55 0 1The wild-type and white-eyed individuals from the F1 generation were then crossed to produce the followingoffspring.F2 23 31 22 24 0(a) Determine the genotypes of the original parents (P generation) and explain your reasoning. You may usePunnett squares to enhance your description, but the results from the Punnett squares must be discussed inyour answer.(b) Use a Chi-squared test on the F2 generation data to analyze your prediction of the parental genotypes. Showall your work and explain the importance of your final answer.(c) The brown-eyed female in the F1 generation resulted from a mutational change. Explain what a mutation is,and discuss…