7. The rigid bar ABCD of negligible weight is initially horizontal, and the steel rods attached at A and C are stress-free. The load P is then applied and there is a temperature change in the steel rods. P = 35 kips with the stresses in the two steel rods equal. Assume that there is no buckling in the rods. The coefficient of linear expansion is 6.5 x 10^-6 per degree F and E = 29 x 10^6 psi for steel.

Question # 4: Determine the state of stress at point A on the cross section at section a-a of the cantilever beam. Show the results in a differential element at the point. ( 2 m a 0.5m 400 KN 100 mm 300 mm 100 mm Section a-a

A steel rod having a length of 50m is suspended vertically from one end. It supports a tensile load of P = 250 kN at the lower end. The unit weight of the steel is 7850 kg/m^3. The allowable tensile stress for steel is 140 MPa. Use E = 200 GPa. Determine the total deformation of the steel rod.

1. The rigid bar ABC is supported by a pin at B and two vertical steel rods. Initially the bar is horizontal and the rods are stress-free. Determine the stress in each rod if the temperature of the rod at A is decreased by 40°C. Neglect the weight of bar ABC. Use a=10.7 x 10-6/°C and E=200 GPa for steel. A = 1500 mm². - A = 500 mm² 1.5 m 1 m A В k 0.8 m → 1.5 m

Determine the maximum stress of the plate. • rivet hole diameter 2 cm • width of the plate= 7 cm • uni-axial tension of 54 MPa

Three aluminum rods support the rigid L-shaped bracket BCF as shown in the figure. Determine the stress in rod DE (express answer in MPa) if rod FG is cooled by 50°C. All three rods have the same cross-sectional area of 1000 mm^2. Use 73.1 GPa and 23 x 10^-6/°C for the modulus of elasticity and the coefficient of thermal expansion of aluminum, respectively.

The solid 1.05-in.-diameter rod is subjected to a uniform axial distributed loading along its length of w = 800 lb/ft. Two concentrated loads also act on the rod: P= 2300 lb and Q = 1400 lb. Assume a = 12 in. and b = 24 in. Determine the normal stress in the rod at the following locations: (a) x = 8 in. (b) x = 24 in. → → -→ P B a Answer: Ox=8in. = psi Ox=24in. = psi

Determine the average axial tensile stress in the bar of the figure below if P=225 kN and the cross sectional area of the bar is 2500 square mm

At a temperature of 34°F, a 0.06 in. gap exists between the ends of the two bars shown. Bar (1) is an aluminum alloy [a = 12.5 x 10-6/°F] and bar (2) is stainless steel [a = 7.3 x 10-6/°F]. The supports at A and C are rigid. Determine the lowest temperature at which the two bars contact each other. (1) 33m B (2) Answer: Final temperature = 55 in. -0.06. gap °F.

The stresses acting on an element are dx = 745 psi, ay = 615 psi, and Txy = 430 psi. (Consider only the in-plane stresses the stresses in the x-y-plane). Oy Determine the principal stresses (in psi) and angle of the principle planes (in degrees counterclockwise from the +x-axis). (For normal stresses, use the deformation sign convention. For maximum shear stress, enter the magnitude.) %1 = psi 0₂ = psi psi max = 8p = Show the stresses on a sketch of a properly oriented element. (Submit a file with a maximum size of 1 MB. Your submission will be graded by your instructor after the due date based on its accuracy. Your grade may change.) Choose File No file chosen This answer has not been graded yet.