### Question 7: Considering the following chemical, which statement is true?**Diagram Explanation:**The diagram depicts an open-chain form of a carbohydrate molecule, most likely a glucose molecule. It contains the following structure:``` CHO | H - C - OH | HO - C - H | HO - C - H | H - C - OH | CH2OH```**Answer Choices:**A. It needs to form the ring form first before it can interact with methanol to form an intramolecular hemiacetal.B. When the molecule forms the ring form, the carbon atom #5 becomes the anomeric carbon.C. Both A and BD. Neither A nor B**Detailed Explanation:**The structure shown is an open-chain form of a monosaccharide. In aqueous solution, this monosaccharide can cyclize to form a ring structure through an intramolecular reaction where the hydroxyl group on one of the carbon atoms (typically the penultimate carbon, in this case, carbon atom #5) reacts with the aldehyde group (located on carbon atom #1). This results in the formation of a hemiacetal.- **Statement A**: This is true. In the formation of a hemiacetal, the molecule usually has to convert to its cyclic form. - **Statement B**: This is incorrect. When the ring forms, carbon atom #1 (the carbonyl carbon) becomes the anomeric carbon, not carbon atom #5.**Correct Answer:**D. Neither A nor BThis transcription and explanation provide an understanding of monosaccharide behavior in cyclization reactions, relevant to the given chemical structure.

Carbohydrates exist in ring form . There are different method of presentation to show this…

7. Considering the following chemical, which statement is true? CHO H-C-OH -C-H HO-C-H H-C-OH CH₂OH A. It needs to form the ring form first before it can interact with methanol to form an intramolecular hemiketal B. When the molecule forms the ring form, the carbon atom #5 becomes the anomeric carbon C. Both A and B D. Neither A nor B

7. Considering the following chemical, which statement is true? CHO H-C-OH -C-H HO-C-H H-C-OH CH₂OH A. It needs to form the ring form first before it can interact with methanol to form an intramolecular hemiketal B. When the molecule forms the ring form, the carbon atom #5 becomes the anomeric carbon C. Both A and B D. Neither A nor B

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question 19.
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