In Exercises 61–64, find an equation for the level surface of the function through the given point. 61. f(x, у, 2) — Vx - у — Inz, (3, —1, 1)62. f(x, y, 2) %—D In (x? + у + z?), (-1, 2, 1)63. g(x, y, z) = Vx² + y² + z², (1,-1, V2)х — у +z2х + у — 2"64. g(x, у, 2)(1, 0, –2)

Since we only answer up to 3 sub-parts, we’ll answer the first 3. Please resubmit the question and…

61. f(x, у, 2) — Vx - у — Inz, (3, —1, 1) 62. f(x, y, 2) %—D In (x? + у + z?), (-1, 2, 1) 63. g(x, y, z) = Vx² + y² + z², (1,-1, V2) х — у +z 2х + у — 2" 64. g(x, у, 2) (1, 0, –2)

61. f(x, у, 2) — Vx - у — Inz, (3, —1, 1) 62. f(x, y, 2) %—D In (x? + у + z?), (-1, 2, 1) 63. g(x, y, z) = Vx² + y² + z², (1,-1, V2) х — у +z 2х + у — 2" 64. g(x, у, 2) (1, 0, –2)

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter1: Fundamental Concepts Of Algebra

Section1.2: Exponents And Radicals

Problem 31E

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Question

In Exercises 61–64, find an equation for the level surface of the function through the given point.

61. f(x, у, 2) — Vx - у — Inz, (3, —1, 1)
62. f(x, y, 2) %—D In (x? + у + z?), (-1, 2, 1)
63. g(x, y, z) = Vx² + y² + z², (1,-1, V2)
х — у +z
2х + у — 2"
64. g(x, у, 2)
(1, 0, –2)

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