6.3-3. Multiple Access protocols (c). Consider the figure below, which shows the arrival of 6 messages for transmission at different multiple access wireless nodes at times t = 0.3, 1.7, 1.8, 2.5, 4.2, 4.6. Each transmission requires exactly one time unit. t=0.0 □ T | r 5 6 3 For the CSMA protocol (without collision detection), indicate which packets are successfully transmitted. You should assume that it takes .2 time units for a signal to propagate from one node to each of the other nodes. You can assume that if a packet experiences a collision or senses the channel busy and that that node will not attempt a retransmission of that packet until sometime after t=5. Hint: consider propagation times carefully here. (Note: You can find more examples of problems similar to this here B.] 4 t=1.0 02 23 t=2.0 t=3.0 5 t=4.0 6 t=5.0

Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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look at the  two q please

6.3A-1. Multiple Access protocols (1). Consider the figure below, which shows the arrival of 6
messages for transmission at different multiple access wireless nodes at times t=0.1, 1.4, 1.8, 3.2,
3.3, 4.1. Each transmission requires exactly one time unit.
t=0.0
U
O
5
6
2
t=1.0
1
2 3
t=2.0
For the pure ALOHA protocol, indicate which packets are successfully transmitted. You can assume
that if a packet experiences a collision, a node will not attempt a retransmission of that packet until
sometime after t=5. [Note: You can find more examples of problems similar to this here B.]
45
t=3.0
6
t=4.0
t=5.0
Transcribed Image Text:6.3A-1. Multiple Access protocols (1). Consider the figure below, which shows the arrival of 6 messages for transmission at different multiple access wireless nodes at times t=0.1, 1.4, 1.8, 3.2, 3.3, 4.1. Each transmission requires exactly one time unit. t=0.0 U O 5 6 2 t=1.0 1 2 3 t=2.0 For the pure ALOHA protocol, indicate which packets are successfully transmitted. You can assume that if a packet experiences a collision, a node will not attempt a retransmission of that packet until sometime after t=5. [Note: You can find more examples of problems similar to this here B.] 45 t=3.0 6 t=4.0 t=5.0
6.3-3. Multiple Access protocols (c). Consider the figure below, which shows the arrival of 6
messages for transmission at different multiple access wireless nodes at times t = 0.3, 1.7, 1.8, 2.5,
4.2, 4.6. Each transmission requires exactly one time unit.
t=0.0
U
[
50
[
n
n
a
3
t=1.0
For the CSMA protocol (without collision detection), indicate which packets are successfully
transmitted. You should assume that it takes .2 time units for a signal to propagate from one node to
each of the other nodes. You can assume that if a packet experiences a collision or senses the
channel busy and that that node will not attempt a retransmission of that packet until sometime
after t=5. Hint: consider propagation times carefully here. (Note: You can find more examples of problems similar to this here
B.)
4
23
t=2.0
4
t=3.0
5
t=4.0
t=5.0
Transcribed Image Text:6.3-3. Multiple Access protocols (c). Consider the figure below, which shows the arrival of 6 messages for transmission at different multiple access wireless nodes at times t = 0.3, 1.7, 1.8, 2.5, 4.2, 4.6. Each transmission requires exactly one time unit. t=0.0 U [ 50 [ n n a 3 t=1.0 For the CSMA protocol (without collision detection), indicate which packets are successfully transmitted. You should assume that it takes .2 time units for a signal to propagate from one node to each of the other nodes. You can assume that if a packet experiences a collision or senses the channel busy and that that node will not attempt a retransmission of that packet until sometime after t=5. Hint: consider propagation times carefully here. (Note: You can find more examples of problems similar to this here B.) 4 23 t=2.0 4 t=3.0 5 t=4.0 t=5.0
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