6. You have a jar full of M&Ms. 8 are Black, 5 are Green, and 3 are Yellow. Let B means you drew a Black, G means you drew a Green and Y means you drew a Yellow. B. Assume you draw one M&M at random for each trial, and do NOT replace it (since you ate it) before the next trial. IV. V. VI. Compute P(2nd Draw is G | 1st Draw is B) Compute P(2nd Draw is G) by the fact [1st Draw is G} and {1st Draw isn't G} are complements of each other Compute P(Draw goes YYYBB)

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6. You have a jar full of M&Ms. 8 are Black, 5 are Green, and 3 are Yellow. Let B means
you drew a Black, G means you drew a Green and Y means you drew a Yellow.
B. Assume you draw one M&M at random for each trial, and do NOT replace it
(since you ate it) before the next trial.
IV.
V.
VI.
Compute P(2nd Draw is G | 1st Draw is B)
Compute P(2nd Draw is G) by the fact [1st Draw is G} and {1st
Draw isn't G} are complements of each other
Compute P(Draw goes YYYBB)
Transcribed Image Text:6. You have a jar full of M&Ms. 8 are Black, 5 are Green, and 3 are Yellow. Let B means you drew a Black, G means you drew a Green and Y means you drew a Yellow. B. Assume you draw one M&M at random for each trial, and do NOT replace it (since you ate it) before the next trial. IV. V. VI. Compute P(2nd Draw is G | 1st Draw is B) Compute P(2nd Draw is G) by the fact [1st Draw is G} and {1st Draw isn't G} are complements of each other Compute P(Draw goes YYYBB)
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Solution:

From the given information, a jar contains 8 black M&Ms, 5 Green M&Ms and 3 yellow M&Ms. Total number of M&Ms is 8+5+3=16. Here, M&Ms are drawn at random without replacement.

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