
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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![**Problem 6:**
The kinetic energy of an electron is 55% of its rest mass energy. Find the speed of the electron.
**Explanation:**
- This problem involves finding the speed of an electron given that its kinetic energy is a specific percentage of its rest mass energy.
- To solve this type of problem, you would typically use the theory of relativity. The rest mass energy of an electron is given by \( E_0 = m_0c^2 \), where \( m_0 \) is the rest mass of the electron and \( c \) is the speed of light.
- The given information states that the kinetic energy \( K \) is 55% of the rest mass energy, \( K = 0.55E_0 \).
- You can relate kinetic energy and speed using the relativistic energy-momentum relationship:
\[ E = \gamma m_0c^2 \]
where \( \gamma = \frac{1}{\sqrt{1 - v^2/c^2}} \) is the Lorentz factor.
- Solving for the speed \( v \) involves substituting \( K = E - m_0c^2 \) into the equations and solving for \( v \).](https://content.bartleby.com/qna-images/question/e4a06524-cdae-4bde-89a8-f8cc3ad05f41/51e587a2-354c-48ee-a5a4-102fe489acc1/z6o8or_thumbnail.jpeg)
Transcribed Image Text:**Problem 6:**
The kinetic energy of an electron is 55% of its rest mass energy. Find the speed of the electron.
**Explanation:**
- This problem involves finding the speed of an electron given that its kinetic energy is a specific percentage of its rest mass energy.
- To solve this type of problem, you would typically use the theory of relativity. The rest mass energy of an electron is given by \( E_0 = m_0c^2 \), where \( m_0 \) is the rest mass of the electron and \( c \) is the speed of light.
- The given information states that the kinetic energy \( K \) is 55% of the rest mass energy, \( K = 0.55E_0 \).
- You can relate kinetic energy and speed using the relativistic energy-momentum relationship:
\[ E = \gamma m_0c^2 \]
where \( \gamma = \frac{1}{\sqrt{1 - v^2/c^2}} \) is the Lorentz factor.
- Solving for the speed \( v \) involves substituting \( K = E - m_0c^2 \) into the equations and solving for \( v \).
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