6. Cra(P207)3a. Calculate it's molar massb. 4.93 mols Cr4(P207)3 =g Cra(P207)3%3Dc. 78.45g Cr4(P207)3 =_molecules Cr4(P207)3d. 7.32x1025 molecules Cra(P207)3 = .g Cra(P207)3%3D

Mole is the amount of the substance that contains the same number of particles or atoms or…

Answered: 6. Cra(P207)3 a. Calculate it's molar…

6. Cra(P207)3 a. Calculate it's molar mass b. 4.93 mols Cra(P207)3 = _g Cra(P207)3 c. 78.45g Cr4(P207)3 molecules Cra(P207)3 d. 7.32x1025 molecules Cr4(P207)3 = g Cra(P207)3

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter4: Calculations Used In Analytical Chemistry

Section: Chapter Questions

Problem 4.13QAP

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Concept explainers

Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.

Question

6. Cra(P207)3
a. Calculate it's molar mass
b. 4.93 mols Cr4(P207)3 =
g Cra(P207)3
%3D
c. 78.45g Cr4(P207)3 =
_molecules Cr4(P207)3
d. 7.32x1025 molecules Cra(P207)3 = .
g Cra(P207)3
%3D

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