55 randomly selected students were asked the number of pairs of shoes they have. Let X represent the number of pairs of shoes. The results are as follows: # of Pairs of Shoes 4 Frequency 3 5 8 6 7 8 5 6 2 9 3 10 11 12 13 14 10 2 6 5 5 Round all your answers to 4 decimal places where possible. 1. What percent of respondents have at least 11 pair of shoes? 2. 68% of all respondents have fewer than how many pairs of shoes?

Q: The answer is 14,575. How can I calculate that, using which formulas?

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A: From the provided information, n1=25x1=72.4s1=14.8n2=25x2=73.9s2=17.9α=0.01

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A: Given The data is as follows: U=100 n(Track Events)=70nField  Events=62Neither=8

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Q: Please provide a NORMAL CURVE for the solution.

A:

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A:

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Q: 3. Find the median of this data set: 6, 4, 2, 3, 1, 5, 8, 8, 9, 6. OA. 5.2 OB. 5 O c. 5.5 OD 6

A:

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A: The probability distribution for the number of Customer per day at the Sunset Spa is shown below:…

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A:

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A: given data  n1 = 2253    x1 = 986p^1 = x1n1 = 9862253 = 0.4376 n2 = 2629    x2 =923p^2 = x2n2 =…

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A: Given that Jenny's z score= -0.56, Nicole's z score=1.13

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A: Given data: 71.7, 72.1, 72.1, 72.1, 73.1, 73.9, 74.2, 75.3, 76.2, 78.5, 79.2, 79.2, 80.1, 80.5,…

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A: qtr t Close 1983 1 1258.64 1984 2 1211.57 1985 3 1546.67 1986 4 1895.95 1987 5 1938.83…

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A: Given that: Use left-hand to write? Male Female Yes 23 65 No 217 455 Significance level,…

Q: A standardized test has a pop. mean of 152 and a standard deviation of 16. Nicole has a score of…

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A: Given that n=4, p=1/4, q=1-p=1-(1/4)=3/4 X~Binomial(n=4,p=1/4) X be the number of customers who go…

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