MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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How to find the simple variance & standard Deviation. Show the work for the simple variance
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- For the residents in 2014, use R to calculate the interval with 99% certainty that the interval contains the actual population mean of the residents by census tracts. Type in the interval with keyboard. We also know that in each year, the number of residents by census tract in the State of Maryland follows a normal distribution, and the variance in the number of residents within the State of Maryland is the same for different years. POP2014: 3072, 1989, 3794, 2689, 3211, 3722, 4385, 4009, 7598, 3862, 3097, 2726, 4881, 4157, 2570, 2512, 2518, 4863, 4147, 7139, 6067, 6819, 3705, 3239, 3824, 4977, 2576, 2940, 9791, 5231, 5634, 5337, 4205, 3888, 5562, 3335, 3770, 1808, 2045, 1532, 5420, 4993, 6109, 4377, 5424, 4976, 4507, 3738, 2827, 3485, 1559, 5199, 4702, 3971, 3803, 3356, 4670, 3816, 5477, 4760, 3126, 3630, 3755, 3795, 2578, 3382, 4005, 2442, 6096, 3799, 3843, 3836, 6046, 6431, 3561, 3142, 4829, 5058, 2471, 6119, 3523, 3094, 3146, 3356, 2618, 2366, 4266, 4016, 6080, 1554, 6878, 3645,…arrow_forwardFill in the Blanks: Applying Chebyshev's Rule to this distribution, we estimate that 75% or more of women with metastatic breast cancer will survive between __________ and __________ years (2 standard deviations from the mean).arrow_forwardActuaries use various parameters when evaluating the cost of a life insurance policy. The variance of the life spans of a population is one of the parameters used for the evaluation. Each year, the actuaries at a particular insurance company randomly sample 30 people who died during the year (with the samples chosen independently from year to year) to see whether the variance of life spans has changed. The life span data from this year and from last year are summarized below. Current Last Year Year x1 = 75.8 | x,= 76.2 si= 47.61 s3= = 92.16 (The first row gives the sample means and the second row gives the sample variances.) Assume that life spans are approximately normally distributed for each of the populations of people who died this year and people who died last year. Can we conclude, at the 0.05 significance level, that the variance of the life span for the current year, of, differs from the variance of the life span for last year, o,? Perform a two-tailed test. Then complete the…arrow_forward
- Actuaries use various parameters when evaluating the cost of a life insurance policy. The variance of the life spans of a population is one of the parameters used for the evaluation. Each year, the actuaries at a particular insurance company randomly sample 30 people who died during the year (with the samples chosen independently from year to year) to see whether the variance of life spans has changed. The life span data from this year and from last year are summarized below. Current Last Year Year *1 = 75.8 x2 = 76.2 s3 = 47.61 s3= 92.16 (The first row gives the sample means and the second row gives the sample variances.) Assume that life spans are approximately normally distributed for each of the populations of people who died this year and people who died last year. Can we conclude, at the 0.05 significance level, that the variance of the life span for the current year, of, differs from the variance of the life span for last year, o,? Perform a two-tailed test. Then complete the…arrow_forwardHow do I interpret the 6 characteristics whith the data given? Column Mean Median Range Variance Std. dev. 1 - Cholesterol 253.92857 268 218 2276.291 47.710492arrow_forwardFor computing the variance this number is called as the value that is added or subtracted from the most probable value a. accuracy b. mistake c. error d. probable errorarrow_forward
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