Table TealsQu rening Mar WordLayoutDesignA AFn-ReplaceViewDeveloperRelerencesMailingiRavewPage LayoutAaBbCcD AabCcDr AaBbCTNo Spaci Heading 1buetChangeStylesAA ESelectEditing14Taes iew Apman1NormalBIU KX Aa -ASlesPuteParagiaphFont50 kN/mQ-1 For the beam loaded asshown in the figure, draw theforce and bending Adiagrams usingmethod of equations. Locateevery important point.Q-2 For the beam loaded asshown in the figure, draw theshear force and bendingdiagrams usingof relationships.inmortant noint.20 kN/mshearmoment2 m2 m2 mRARo121020 kN10 kN/m40 kN1 m2 mmomentmethod2 m2m1 mWoPogr I arEnglish Unted Stated160%(-17:25796

Given: To draw the shear force and bending moment diagram. NOTE: According to Bartleyby's policy we…

50 kN/m 20 kN/m Q-1 For the beam loaded as shown in the figure, draw the shear force and bending A diagrams method of equations. Locate n important point. B. moment using 2 m 2 m 2 m Ro RA 20 kN 40 kN

50 kN/m 20 kN/m Q-1 For the beam loaded as shown in the figure, draw the shear force and bending A diagrams method of equations. Locate n important point. B. moment using 2 m 2 m 2 m Ro RA 20 kN 40 kN

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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6 30.| zain IQ bäð öeljäll - 2_5217624247974759356.pdf ビン Cumaression -5ッ7.o46 +3.M N.A Coupression Tens.'on Teusiou HiWi A beam with I cross-Section is Subjected to negative bending moment M: 50 k.m.The Cross sectioncel dimensions of the beam are shown. Determine the magnitude of maximum pendling stress. loumm 120 mm و من ۹
OK EFyz0 Example The figure shows two rollurs and in equilibrium. Find the valus of the reachion foras Ra and Ry of the rollers on the beam. The beam is weightluss. laterally loaded beam which is supported by a 400N 800N 200N 10ON 800 min So 000 m Solution 200 mm 300 mm 800N EFy z0 400N 200N joON 0-3 2.7 Ra tR - 200 - 400+ 100 -800 =0 Ra Rat Ry s 1300 Ra 1300- Rb ZMa z0 -(200x 0.6) + (400 0-2) - (100* 0.7) -(R 1) + (800 * ) = 0 - 120 + 80 -70 - R + 1360 -0 RE. 1360 t80 -120-10 1250 N * Ra : 13o0 - 1250 = 50 N. HW Repeat the Salution by taking the moment a boud O O General two dimen sional_fora system Fx=0, ZFy
A rigid weightless be am SUPPorted at the point D by the pixed goint loo ded by the momend M is Support and points B and c holding the beam horisonta lly . a + the ver tical bs connected are For the data listed below determne ! Data > E = 2.1x10$ MPa gie ld stres 6y: 250 MPa , foctor oc Sofety Sr-1.S * Necessoy are a wetion A ? Of Cross - Other Data ; I 5 cM , a : U cm Ma SONM Safety · design method ond limit-state- mordatory. * Use both, Factorr design netled. Both net hats A.E 2A a
FIGURE PS-55 25 K 15 K 6 ft 4 ft 3.0K/ft 4 Use the free body diagram pproach shown in Sections 5-3 through 5-5 to determin the internal shearing force and bending moment al any speecified point in a beam. nd bending moneat diagrams using the guidelines pre- sented in Section 5-10.
Haw-3 The compressiv Stresf (r)of a rectangular beam sectionis given by the fakmula: 6 M bh where Mis bending moment (24 x1 N-mm Pi axiat ferce (6x1o° N) , b is widthof section (30o mm) and h is height of Section (600 mm),if the errok in measuring (M)is +3-6 x lo° N-mmekkak in measuring (P) ir +18x1 x lo N anderror in measuring each (6) and h) 9 mmyuse khe tatat derivative to find the tatal is
[Q2]( problem 3/6 ip131) to 2No O كطة التطب The (450 kg) uniform beam AB Supports the 5.6 m 2.4 m- (220 kg) load as Shown. Determine the reactions 2Nof 220 kg at the supports A´ and B Ane Ax = Hy = 1324.3 N, B= 3090.2 N. %3D
the spring LAB, KABLS unkmeen. what would be the st AB 23:40 ON l 21% l You Just now The two springs (AB) and (ACI are shown in figure a below. in their orieinal unstretched poscon. After e applica of a force F the stretched pasition is shawn in fuure ibi ed of spring (ACACI= 200 tt he sie 3 ft
400Ib 300 lb 20030 20015 A 30 10 10' 10' 2000 lb Fig. 2-1
> Next question You can retry this question below A triangular distributed load of max intensity w-490 N/m acts on beam AB. The beam is supported by a pin at A and member CD, which is connected by pins at C and D respectively. Determine the reaction forces at A and C. Enter your answers in Cartesian components. Assume the masses of both beam AB and member CD are negligible. cc 030 BY NC SA 2016 Eric Davishahl Variable Value 6.6 m a b C D 11.88 m 4.95 m Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. The reaction at A is A = -11268.69 N. The reaction at Cis C= 11268.69 N. 20 Submit Question Jump to Answer X2-3923.92 B X2+ -8451.52 H X X
force, the sign convention is same as that used in lectures and seminars). A simply supported beam is loaded as shown in the Figure. The corresponding SFD and BMD would be: 20 kN 10 kN/m 2 m 2 m 30 kN (a) 40 kN m 30 kN 30 kN 10 kN (b) 40 kN.m 10 kN 30 kN 30 kN Click Save and Submit to save and submit. Click Save All Answers to save all answvers.
I need quick solution includes Free body diagram. [Moment]
4 A water pipe is to beconstructed with a 207 grade in the novth divection and a 10% grade in the cast divection. Deteomint the angle & reguived in the wafer pipe tor the turn from novth to east. Est 5 Find the length and divection for (uxv) X(vxu) 19 for the tollowtings O u=zi+3j , v= -i+j @ u=2i-2j ++k vーit)-2K ® u= irj-K, v=0 @ u= -gi -2j-4K, v= 2i+2j+k O u= i-tjtk, v= i+j+2k Find @the area of the triange determined by the point P,a & R. Othe unit vector perpendicular toplane PaR. O PU, 1,1), Q(2,1,3), R(3,-1,1) @ P (2,-2, 1) , Q (3,-1,2), R(,-1,1) O P(-2,2,0), Q(0,1,-1) , R (-1,2,-2) A Find the volumo of the parallelopiped Cbon) dek mincl by U,v, ond w. u= 2i , v=2j, w= 2k O uz i-j k, v= 2itj-2K, w= -i+2j-k ® u= 2i+j, v=zi-j+k, w= i+2K i+j-2K , v=-i-k, W= zi+4j -2K 8 Let u= 5i-j+k, v=j-5k, w= -isi+3j-3k. Which verdns. if are @ perpendicular ® paralled. T Find the aveas ☺ All,o), B(0,1),<(-l,0), D(0,-1) A (010) , TS (7.3) , e(9,8), D(2,5) A(-12) , B (2,0) , c(7i1) ,D(4,3) of the…