5. What is the percent yield when 15.5 g of H2SO4 reacts with excess Al(OH): to produce 12.8 g of Ab(SO4)3 and water. 3 H2SO4 + 2 Al(OH): → Al(SO4)3 + 6 H2O (For this problem, you WILL need a stoichiometric setup: MAP the equation above and use the setup to predict the THEORETICAL YIELD of aluminum sulfate before calculating the PERCENT YIELD)

Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter4: Chemical Reactions
Section: Chapter Questions
Problem 4.62P: 4-62 Iron ore is converted to iron by heating it with coal (carbon), and oxygen according to the...
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Hi, I need help with this problem pls and my teacher is so bad at explaining how to setup the problem and getting the answer for them if you can help me I will appreciate it so much.
5. What is the percent yield when 15.5 g of H2SO4 reacts with excess Al(OH): to
produce 12.8 g of Alb(SO4)3 and water.
3 H2SO4 + 2 Al(OH): Al (SO4)3 + 6 H2O
(For this problem, you WILL need a stoichiometric setup: MAP the equation
above and use the setup to predict the THEORETICAL YIELD of aluminum sulfate
before calculating the PERCENT YIELD)
Transcribed Image Text:5. What is the percent yield when 15.5 g of H2SO4 reacts with excess Al(OH): to produce 12.8 g of Alb(SO4)3 and water. 3 H2SO4 + 2 Al(OH): Al (SO4)3 + 6 H2O (For this problem, you WILL need a stoichiometric setup: MAP the equation above and use the setup to predict the THEORETICAL YIELD of aluminum sulfate before calculating the PERCENT YIELD)
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