5. Use the superposition theorem and solve for the following... a. current contribution of S1 to R1 b. current contribution of S1 to R2 c. current contribution of S1 to R3 d. current contribution of S1 to R4 e. current contribution of S2 to R1 f. current contribution of S2 to R2 g. current contribution of S2 to R3 h. current contribution of S2 to R4 i. current contribution of S3 to R1 j. current contribution of S3 to R2 k. current contribution of S3 to R3 I. current contribution of S3 to R4 S1 12 www 10 Ω R1 20 V R2 R3 www ww 11 622 ELECTRONIS HUS S2 12 V 492 4 A 13 R4 S3

Kirchoff's Law. Please answer in GRESA format. Thankyou

Instead of thinking of an adder as adevice that adds two numbers and then links thecarries together, we can think of the adder as ahardware device that can add three inputs together(ai, bi, ci) and produce two outputs (s, ci + 1). Whenadding two numbers together, there is little we can dowith this observation. When we are adding more thantwo operands, it is possible to reduce the cost of thecarry. The idea is to form two independent sums, calledS′ (sum bits) and C′ (carry bits). At the end of theprocess, we need to add C′ and S′ together using a normal adder. This technique of delaying carrypropagation until the end of a sum of numbers is calledcarry save addition. The block drawing on the lowerright of Figure B.14.1 (see below) shows theorganization, with two levels of carry save addersconnected by a single normal adder.Calculate the delays to add four 16-bit numbers usingfull carry-lookahead adders versus carry save with acarry-lookahead adder forming the final sum. (The timeunit T…

Problem Solving: Simplify and determine the equivalent circuit resistance below: R₁=200 E= 460 V R5= 1000 R₂ = 1000 R3 = 1000 R4 = 100 R6 = 1500 Rg = 600 R7 = 200 R12= 200 R8 = 4000 R10 = 400 {R₁1 = 200 R13=2000 R₁4 = 400 R15 = 1000 www R16 = 2000 m R17 = 6000 R18 = 1040 R19 = 104 Hi guys! Here is something you can practice with. Simplify the circuit above. The final answer for this is 153/3 ohms. Good luck!

An Euler path, in a graph or multigraph, is a walk through the graph which uses every edge exactly once. An Euler circuit is an Euler path which starts and stops at the same vertex. Our goal is to find a quick way to check whether graph (or multigraph) has an Euler path or circuit. 1. Which of the graphs below have Euler paths? Which have Euler circuits?

1) What is a half adder? 2) What is a full adder? 3) What are the applications of adders? 4) What is a half subtractor? 5) What is a full subtractor? 6) What are the applications of subtractors? 7) Obtain the minimal expression for above circuits. 8) Realize a full adder using two half adders 9) Realize a full subtractors using two half subtractors

The characteristic equation of a system is found to be: s2 (s4 + 5s² + 3s + 1) How many Root LOcus branches we have for this system? O a. 5 branches O b. 4 branches Oc. 2 branches O d. 6 branches O e. 3 branches

Explain clear steps by steps

Generate at random simple graphs with 10 vertices. Stop when you have constructed one with an Euler circuit. Display the Euler circuit. (Hint: use Matlab function graph) Please do not copy any existing responses. Respond in 1 hour to receive upvote.

L-1 loge s2+1 s2+9 = .......