5. The railway crossing gate consists of the 100 kg gate arm having a centre of mass at Ga and the 250 kg counterweight having a centre of mass at Gw as shown in the Figure. Determine the magnitude and directional sense of the resultant moment produced by the weight about point A. Determine the magnitude and direction sense of the resultant moment produced by the weight about point B?

The rigid pipe is subject to the following loads. Neglecting the weight of the pipe, determine the moment at O. SOLVE THE FF Vector component form of 50-lb force (ANSWER: 25.000i +0j -43.30k lb) Magnitude of the resultant force (ANSWER: 78.10 lb) Position vector of the 50-lb force from point O to its point of application on the pipe. (ANSWER: -15i -10j +12k inch) Moment at point O, in vector component form. (ANSWER: 1153.01i -829.52j +250.00k lb-in)

The weight of a 20 lb oven door acts vertically through point D. The door is supported by a hinge at point A and two springs are symmetrically located on each side of the door. The resultant moment about point A of the weight and spring forces is zero. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. 8 in. 12 in. 5 in. -10 in.- = Based on the values of Fobtained for a 45° and a 90°, determine the stiffness of the springs. (Round the final answer to four decimal places.) The stiffness of the springs is [ lb/in.

A 7 m long steel shaft weighing 250 kg is supported at points A and B as shown in the figure. If the weight of the shaft acts at point G, determine the moment of the weight about point A in Cartesian form. Assume the point G is located at the coordinates (1m,3m,1.5m) & if the support at B creates a reaction force Bx and By as shown, determine these reaction forces. Assume B is located at 3 m from the origin O along the z-axis

4) Determine the total moment caused by the forces Fp4 and Fca about the plate diagonal that goes through point B (the dashed line). Write your answer in cartesian vector notation. FCA= 500 lb 14 ft FRA = 350 Ib FDA= 400 lb 3 ft-> 3 ft 3 ft 2 t 6 ft

and For problem above, Replace the loading on the system below by a single resultant force. Find the points on the x- and y – axes through which the resultant force must pass.

Using the principles to be developed in Chapter 3 on equilibrium, one can determine that the tension in cable AB is 289.8 N. Determine the moment about the x-axis of this tension force acting on point A. Compare your result with the moment of the weight W of the 25- kg uniform plate about the x-axis. What is the moment of the tension force acting at A about the line OB? 0.38 m Mx = Answers: 0.57 m i -74.047 (Mx)w= MOB -63.853 0 A 0.51 m W 25 kg 23⁰ 0.92 m N-m N-m N•m

A 7 m long steel shaft weighing 250 kg is supported at points A and B as shown in the figure. If the weight of the shaft acts at point G, determine the moment of the weight about point A in Cartesian form.AssumethepointGislocatedatthecoordinates(1m,3m,1.5m)