The cable exerts a force P at the end of the crane boom. Determine the position of the boom so that force P creates a maximum moment about point O. What is this moment?
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Solution:
Given Data:
To Find:
(a) The position of the boom.
(b) The magnitude of the moment.
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- The structure is supported by a pin at C and a cable attached to A. The cable runs over the small pulley D. Find the internal force systems acting on sections 1 and 2.The L-shaped rod AOCD has an 80 kg mass hanging from it at B. The rod is leaning against a smooth wall at A. Point B is half way up OA. There is a journal bearing at C and a thrust bearing at D. They are properly aligned. A force F is pulling in the x-direction at B. Just as the rod comes off of the wall at A, what is the magnitude of the force F. 1 m B F 1mThe figure shows the Russel fracture traction device and a mechanical model of the leg. The leg is held in balance in the position indicated by the two weights attached to the two cables. The combined weight of the leg and cast is W=180 N. The horizontal distance between points A and B where the cables are attached to the leg is L=100 cm and the vertical distance is d=5 cm. Point C is the center of gravity of the cast and leg at three quarters of the L measured from point A (3L/4= 75 cm). The angle that cable 2 makes with the horizontal is measured as β=30°. Accordingly, in order for the leg to remain in balance in the shown position; a) Find the tensile force T1 in cable 1. (Write your result in N) Answerb) Find the tensile force T2 in cable 2. (Write your result in N) Answerc) Find the angle α of cable 1 with the horizontal. Response
- Find the forces in the three members of the space truss shown in the figure. 600 mm 500 mm 820 mm- 550 mm 625 mm 950 NThe figure shows a mechanical model of the Russel fracture traction device and the leg. The leg is held in balance in the position indicated by the two weights attached to the two cables. The total weight of the leg and the cast is W=200 N. The horizontal distance between points A and B where the cables are attached to the leg is L=100 cm and the vertical distance is d=10 cm . Point C is the center of gravity of the cast and leg at three quarters of the L measured from point A ( 3L/4= 75 cm) . The angle that cable 2 makes with the horizontal is measured as β=40 ° . Accordingly, in order for the leg to remain in balance in the position shown; a) Find the tensile force T 1 in cable 1 . (Write your result in N ) b) Find the tensile force T 2 in cable 2 . (Write your result in N ) c) Find the angle α of cable 1 with the horizontalHOME WORK 3 Determine the resultant force at A. for the figure below Hint : 1- Find the position of all points A,B,C (x, y, z) 2- Find FAR and FAC 3- Find |raR| and Iracl 4- Find FAR = F UAB and FAC = F UAC 5- Finally find R and a, B,Y 3m Fc= 500N FB= 500N 3m 5m 3m B 4m 2m 5m
- The figure shows the Russel fracture traction device and a mechanical model of the leg. The leg is held in balance in the position indicated by the two weights attached to the two cables. The combined weight of the leg and the cast is W=210 N. The horizontal distance between points A and B where the cables are attached to the leg is L=100 cm and the vertical distance is d=6 cm. Point C is the center of gravity of the cast and leg at three quarters of the L measured from point A (3L/4= 75 cm). The angle that cable 2 makes with the horizontal is measured as β=33°. Accordingly, in order for the leg to remain in balance in the shown position; a) Find the tensile force T1 in cable 1. (Write your result in N) b) Find the tensile force T2 in cable 2. (Write your result in N) c) Find the angle α of cable 1 with the horizontal.The figure shows the finishing position of a body builder's arm who is performing a standing lateral raise with a 5.00-kg dumbbell. This is an excellent exercise that isolates the lateral deltoid muscle. The weight of the arm itself is 42.5 N, and it acts at point A in the figure. Given the information shown, and the fact that 0 = 9.74°, (a) find the magnitude of the tension force in the deltoid (F₁) and (b) the normal force from the shoulder joint (F acting on the humerus bone that holds the arm in this equilibrium position. S (a) Number (b) Number i Fa 0.075 m O 12⁰ 0.250 m Units Units W arm 0.510 m 5 kg WAThe figure below shows a painting hanging from a nail fixed into the wall. The picture is supported by a strong, light string attached to the picture symmetrically at two points along the top of the frame. 0.1 m 420 42 05 m 0.75 m Draw a free-body diagram of the painting. If the tension in the string is 60 N, what is the weight of the painting? A person tries to move the painting to the right by pushing on the bottom left edge with a force of 10 N. What moment does this exert about the nail? What force would the person need to apply to the top left edge instead to exert the same moment?
- A sukelco post is subjected to forces acting upon it due to electrical cables attached to it. F1=60N north, F2=80N west and F3=120N, 45° south west. at what direction and force shall a buy wire be located to prevent the toppling?The wheels, axle, and handles of a wheelbarrow weigh W = 55 N. The load chamber and its contents weigh WL = 623 N. The drawing shows these two forces in two different wheelbarrow designs. To support the wheelbarrow in equilibrium, the man’s hands apply a force to the handles that is directed vertically upward. Consider a rotational axis at the point where the tire contacts the ground, directed perpendicular to the plane of the paper. Find the magnitude of the man’s force for both designs.An eye bolt is used to attach 3 cables to a steel plate. The tension in the three cables create F1=200 lbf, F2=250 lbf, and F3=100 lbf with 0 = 30 degrees and p=24.1 degrees. If the eye bolt is in equilibrium, what is the x-component of the sum of other forces on the bolt (force from the nut and plate on the bolt) ? If you add up the three force vectors, the sum other force you are looking for will just be in the opposite direction to put the eye bolt in equilibrium. The x-direction is positive to the right. For example, if you find the sum of forces 1, 2, and 3 are 100 Ibf to the right, then the other forces in the x-direction must be pointing to the left (-100 lbf) to put the eye bolt in equilibrium. Eye bolt 2steel 3 plate Nut t Wonsher