5. The following compound is a mono-substituted aromatic hydrocarbon with formula C9H1 Give its structure and assign the chemical shift values. H NMR 60 MHz 200 100 Integral=5 Integrat = 6 Integral – 1

Organic Chemistry
9th Edition
ISBN:9781305080485
Author:John E. McMurry
Publisher:John E. McMurry
Chapter13: Structure Determination: Nuclear Magnetic Resonance Spectroscopy
Section13.SE: Something Extra
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5. The following compound is a mono-substituted aromatic hydrocarbon with formula C9H12.
Give its structure and assign the chemical shift values.
TH NMR
60 MHz
-200
100
Integral5
Integral = 6
Integral-1
CgH12
8.0
7.0
0.0
5.0
4.0
3.0
2.0
1.0
O PPM
Transcribed Image Text:5. The following compound is a mono-substituted aromatic hydrocarbon with formula C9H12. Give its structure and assign the chemical shift values. TH NMR 60 MHz -200 100 Integral5 Integral = 6 Integral-1 CgH12 8.0 7.0 0.0 5.0 4.0 3.0 2.0 1.0 O PPM
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