Determine the chemical formula for thefollowing molecules by counting the Carbon,Hydrogen and Oxygen atoms.Determine if the molecule is a carbohydrateby checking the ratio of atoms.5. HoC1H-C-OHH-C-OHH-C-OHCH₂OH6.CH₂OHHO-C=0[H-C-OHH-C-OH1H-C-DHIH - COHIH-C-HIHChemical formulaCarbohydrate ?Chemical formulaCarbohydrate ?

Carbohydrates are molecules containing the elements Carbon, Hydrogen and Oxygen which generally have…

Answered: 5. н., с Н-С-ОН H-C-OH H -C-OH I CH2OH…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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Part C The L isomer of H-C-OH H-C-OH H-C-OH О CHO О О О CH₂OH OH OH OH OH OH Submit OH ОН OH O OH OH O. OH OH OH O OH OH OH OH OH OH OH Request Answer
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Aldose monosaccharides can be oxidized when treated with a mild oxidizing agent. In this reaction, the aldehyde group of the open-chain aldose is oxidized to a carboxylic acid group. In basic solution, ketose monosaccharides can also be oxidized, forming carboxylic acids because they can undergo a rearrangement to an aldose form. Monosaccharides (cyclic hemiacetals) can also react with an alcohol to form acetals, called glycosides, and water. In this reaction, the OH of the anomeric carbon is replaced by the OR group of the alcohol. D-ribose (Figure 1) is treated with a mild oxidizing agent. Edit the structure for D-ribose to show the product of this reaction. M Edit the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars. The single bond is active by default. Include all hydrogen atoms. ► View Available Hint(s) [1] A H 12D H H H H 7 L EXP. CONT.i L 1 -O-H O H ew -O-H enodic Table -O-H H C N O S CI Br I P F
Which of the following organic compound doesnot dissolve in water? glycerol propane propanoic acid propanol H H-C Н Н H-с-с-с Н- OH HICIH H-C c-c 1 Н OH H -+ Н HICIH H Н H H C C H H OH 5-о-т OH -C-H -H OH
13
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What is this lipid? What test wll identify this?
eE-EE. E= AaBbCcI AaBbCcI AaBbCC AaBbCc[ AaB 1 Normal 1 No Spac. Heading 1 Heading 2 Title Styles Paragraph 8 1 9. 10. 1 11: I 2.1 13 14 1 15 1 16 17 2.1 3 I 4 1 5 1 6I General Formula Structure Type of organic compound 8. CH3- CH,-C-H 9. H3C CH3 CH3 H3C ĊH3 O=U
1. (a) Arrange the following lipid molecules in the order of their relative melting points. Н.С — о-С-R Н.С — о-С-R H,C -0-ć- | НС —0—С-R НС —о-с-R' НС —о-с-R" H2C -0-Ċ-R H2C -0-C-R H2C -0-ċ-R" VI VII VIII (-olx). 0-ċ-R 180 —о-с-R 18-1 cisÃ9 -ċ-R") = 18:1transA9 (b) Give your reasons for your answer. (c) On heating lipid VI with aqueous NAOH, all the ester linkages were hydrolyzed. Draw the structure of each product of the hydrolysis. (e) Giving a reason for your answer, predict what would happen to the solubility of these products in water if, after the hydrolysis, excess acid was added to the medium to acidify it.
MACROMOLECULES Summary Chart Macromolecule Monomer Polymers Bonds Functional Groups Examples CH20H CH2OH HO OH он H/. он -0- CH,-CH-CH,-CH,-CH- CH- CH- -CH,- CH;-CH,-CH,- CH, -CH,-CH, H-C -o H-c-0-C-cH,- CH-CH-CH CH,-CH CH H-N-CH- CH-C-OH R1 Rm AGCT 0- CH 0-P=0 AGCT KH H H OH H H.
H,N. NH3 HO, H,O H,N. NH2 COOH СООН glutamic acid glutamine why does the reaction not proceed?
What carbon, by number designates the aldehyde group? * CH,OH C=0 HO- -H- Но- -H- H- -ОН ČH,OH Carbon 1 O Carbon 2 O Carbon 3 Carbon 4 Carbon 5 Carbon 6 None of the above

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5. н., с Н-С-ОН H-C-OH H -C-OH I CH2OH Chemical formula Carbohydrate?