MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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- Students in an experimental psychology class did research on depression as a sign of stress. A test was administered to a sample of 30 students. The scores are given. Complete parts (a) through (c) below. 44 43 32 17 32 43 38 15 58 46 54. 14 (a) Find the mean and median of the data. The mean is 27 34 41 53 31 23 GRAPE (Round to three decimal places as needed.) 48 31 35 28 33 25 28 53 34 28 16 37 19arrow_forwardThe weights (in pounds (lb)) of 52 randomly selected NFL football players are presented below. 305 265 287 285 290 235 300 230 195 236 244 194 190 307 218 315 265 210 194 216 255 300 315 190 185 183 313 246 212 201 308 270 241 242 306 237 315 215 200 295 187 204 257 185 255 318 230 316 200 324 245 185 We would like to construct a 90% confidence interval for the mean weight of NFL football players. Explain why it is not necessary to assess normality for this sample Write an interpretation for your confidence interval, including units if appropriate. You may round the upper and lower limits to the nearest whole number. Does the confidence interval estimate the mean weight for the sample of 52 NFL players or for the population of NFL players? Explain.arrow_forward2. The following are the IQ test scores of 31 randomly selected business students in a certain university. 113 99 104 89 102 91 114 114 103 105 106 108 130 120 131 110 127 118 119 87 73 111 103 74 112 107 103 98 96 112 113 Estimate the mean IQ score for all business students using the following: a. 99% confidence interval b. 95% confidence intervalarrow_forward
- The NIH wants to compare the mean weight loss for five different diets. They measure the weight loss (in pounds) of 5 women assigned to each of the diets for one month. The resulting data set is below. Pounds Diet 2.2 1 0.3 1 0.6 1 1.9 1 -1.2 1 0.1 2 -1.1 2 -1.2 2 1.1 2 2.7 2 1 3 -0.4 3 -0.2 3 0.1 3 -2 3 -2.8 4 -0.1 4 -1.1 4 -1.8 4 -2.9 4 -1.2 5 -1.2 5 -1.7 5 -0.9 5 -1.2 5 a) What is the F statistic for the ANOVA? b) Using a 0.01 level of significance, what is the critical point that one would compare to the F statistic in order to make a conclusion? c) What is the P-value from the ANOVA?arrow_forwardFifteen randomly selected college students were asked to state the number of hours they slept the night before. The resulting data are: 6 16 7 8 7 796 3 11 9 15 4 7 9 a) Find the mean. b) Find the median. c) Find the standard deviation. d) According to Chebysev's Theorem, at least 75% of the times will fall between what two amounts? Is the theorem accurate for this set of data? Why of Why not? e) Are any of the reported hours "unusually" high? Are any of the reported hours unusually low?arrow_forwardThe owner of Maumee Ford-Volvo wants to study the relationship between the age of a car and its selling price. Listed below is a random sample of 12 used cars sold at the dealership during the last year. Car Age (years) Selling Price ($000) 1 11 12.1 2 8 10.5 3 14 5.7 4 17 4.9 5 9 5.0 6 8 13.4 7 10 10.5 8 14 9.0 9 13 9.0 10 17 4.5 11 6 12.5 12 6 11.5 Click here for the Excel Data Filea. Determine the regression equation. (Negative amounts should be indicated by a minus sign. Round your answers to 3 decimal places.) a= b= Estimate the selling price of an 7-year-old car (in $000). (Round your answer to 3 decimal places.) Interpret the regression equation (in dollars). (Round your answer to the nearest dollar amount.)arrow_forward
- The numbers of faculty at 32 randomly selected state-controlled colleges and universities with enrollment under 12,000 students are shown below. Use the data to estimate the mean number of faculty at all state-controlled colleges and universities with enrollment under 12,000 with 92% confidence. Assume o=165.2 211 384 396 211 224 337 395 121 356 621 367 408 515 280 289 180 431 176 318 836 203 374 224 121 412 134 539 471 638 425 159 324arrow_forwardThe following box plot represents a sample of house prices. House prices ($1000s) 160 Find and interpret the first quartile Q1. 155 Ex: 19000 150 Pick 145 Pick 25% of the house prices fall above Q1. Find al 25% of the house prices fall below Q1. Q1 is the median value. 140 135 Pick 130 125 120arrow_forwardListed below are the ages of randomly selected race car drivers. Construct a 98% confidence interval estimate of the mean age of all race car drivers. Assume that this data is normally distributed. 32 32 33 33 41 29 38 32 33 23 27 45 52 29 25 PLEASE SHOW ALL WORK!!!arrow_forward
- Use the results from a survey of a simple random sample of 1064 adults. Among the 1064 respondents, 69% rated 13 themselves as above average drivers. We want to test the claim that more than 20 of adults rate themselves as above average drivers. Complete parts (a) through (e). A. No. Assuming quality of driving can be quantified, half of all adults must have driving quality less than or equal to the mean. B. Yes. Assuming quality of driving can be quantified, a distribution that is extremely skewed to the right would be the most promising scenario for more than this proportion of adults to have driving quality that is above the mean. C. Yes. Assuming quality of driving can be quantified, a distribution that is extremely skewed to the left would be the most promising scenario for more than this proportion of adults to have driving quality that is above the mean. O D. No. It is impossible to compare the quality of different adults' driving. b. If we use the same significance level to…arrow_forwardThis problem will take you through calculating the mean for grouped data by hand.The reason that the class midpoint is used in the table below is because it is the expected value for the average score in each class. Part A: Lower Class Limit Upper Class Limit Frequency Class midpoint Frequency times midpoint 40 44 1 45 49 3 50 54 4 55 59 11 57 627 60 64 20 62 1240 65 69 13 67 871 70 74 7 72 504 75 79 7 77 539 80 84 1 82 82 Part B: Now add up the last column of the table above. Part C: Now add up the third column of your table. Part D: Now divide your answer to Part B by your answer to Part C. This is the mean for the Grouped Frequency Data Table (GFDT).arrow_forwardPavanarrow_forward
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