MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
Bartleby Related Questions Icon

Related questions

Question
**Example of Poisson Distribution in a Maternity Hospital Setting**

In a maternity hospital, the Poisson distribution is used to estimate the number of births expected during the night. The hospital handles 3000 deliveries annually. If these occur randomly throughout the day, approximately 1000 deliveries are expected between midnight and 8:00 a.m. It's crucial during these hours to ensure adequate staffing.

The average number of nightly deliveries is calculated as 1000/365, which equals 2.74. Using the Poisson distribution, the probability of delivering 0, 1, 2, etc., babies per night can be determined. Here are some calculated probabilities:

- **P(0)**: \(2.74^0 \cdot e^{-2.74} / 0! = 0.065\)
- **P(1)**: \(2.74^1 \cdot e^{-2.74} / 1! = 0.177\)
- **P(2)**: \(2.74^2 \cdot e^{-2.74} / 2! = 0.242\)
- **P(3)**: \(2.74^3 \cdot e^{-2.74} / 3! = 0.221\)

**Questions:**

(i) On how many days in the year would five or more deliveries be expected at night?

(ii) Over the course of one year, what is the expected number of deliveries in any day?

(iii) Why might the pattern of deliveries not follow a Poisson distribution?
expand button
Transcribed Image Text:**Example of Poisson Distribution in a Maternity Hospital Setting** In a maternity hospital, the Poisson distribution is used to estimate the number of births expected during the night. The hospital handles 3000 deliveries annually. If these occur randomly throughout the day, approximately 1000 deliveries are expected between midnight and 8:00 a.m. It's crucial during these hours to ensure adequate staffing. The average number of nightly deliveries is calculated as 1000/365, which equals 2.74. Using the Poisson distribution, the probability of delivering 0, 1, 2, etc., babies per night can be determined. Here are some calculated probabilities: - **P(0)**: \(2.74^0 \cdot e^{-2.74} / 0! = 0.065\) - **P(1)**: \(2.74^1 \cdot e^{-2.74} / 1! = 0.177\) - **P(2)**: \(2.74^2 \cdot e^{-2.74} / 2! = 0.242\) - **P(3)**: \(2.74^3 \cdot e^{-2.74} / 3! = 0.221\) **Questions:** (i) On how many days in the year would five or more deliveries be expected at night? (ii) Over the course of one year, what is the expected number of deliveries in any day? (iii) Why might the pattern of deliveries not follow a Poisson distribution?
Expert Solution
Check Mark
Knowledge Booster
Background pattern image
Similar questions
Recommended textbooks for you
Text book image
MATLAB: An Introduction with Applications
Statistics
ISBN:9781119256830
Author:Amos Gilat
Publisher:John Wiley & Sons Inc
Text book image
Probability and Statistics for Engineering and th...
Statistics
ISBN:9781305251809
Author:Jay L. Devore
Publisher:Cengage Learning
Text book image
Statistics for The Behavioral Sciences (MindTap C...
Statistics
ISBN:9781305504912
Author:Frederick J Gravetter, Larry B. Wallnau
Publisher:Cengage Learning
Text book image
Elementary Statistics: Picturing the World (7th E...
Statistics
ISBN:9780134683416
Author:Ron Larson, Betsy Farber
Publisher:PEARSON
Text book image
The Basic Practice of Statistics
Statistics
ISBN:9781319042578
Author:David S. Moore, William I. Notz, Michael A. Fligner
Publisher:W. H. Freeman
Text book image
Introduction to the Practice of Statistics
Statistics
ISBN:9781319013387
Author:David S. Moore, George P. McCabe, Bruce A. Craig
Publisher:W. H. Freeman