Chemistry
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ISBN: 9781305957404
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Transcribed Image Text:5.
Electronegativity
a. Draw the molecular orbital diagram for NO, using the MO
order for O2 and higher diatomics. 5b. Calculate the bond order for NO.
3.0
3.5
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- 3 5. Use the molecule below to answer the questions about atomic and hybrid orbitals. You answer should be chosen from the following: s, p, sp, sp?, or sp³. H-N-C=C-H orbital and a(n) a. The bond between nitrogen and hydrogen is due to overlap of a(n) orbital. b. The lone pair on nitrogen is in what type of atomic orbital? orbital and a(n) orbital. c. The bond between N and C is due to overlap of a(n) orbitals. d. The n-bonds between the two carbon atoms are due to the overlap of Page of 4 507words DGarrow_forwardIII. Draw the hybridized orbital models for the following. Please ensure that you indicate the formal charges, the hybridization of the atoms, bond angles, geometry, and the bond types. a. CO b. H X Harrow_forwardFor F2 draw and label its molecular orbital diagram. 1. Is the molecule paramagnetic? Give an explanation. 2. What is the bond order for F2?arrow_forward
- Please help me understand this. The bond angles in the H3O+ion are: A. 120oB. 90o, 120oC. 109oD. 180arrow_forwardWhat is the hybridization of the atoms in the following compound? O 3 HO 1 2 O a. C1 (sp²), C2 (sp³), C3 (sp²), C4 (sp) O b. C1 (sp²), C2 (sp²), C3 (sp²), C4 (sp³) O c. C1 (sp²), C2 (sp³), C3 (sp³), C4 (sp³) O d. C1 (sp²), C2 (sp²), C3 (sp³), C4 (sp³) O e. C1 (sp³), C2 (sp³), C3 (sp³), C4 (sp³) 4arrow_forward7. MO Theory. Fill in the MO diagrams, determine the MO bond order, and indicate which molecules/ions are paramagnetic or diamagnetic110 THL dlatomic 0,- вс Liz MO diagram MO bond order paramagnetic diamagneticarrow_forward
- Methylamine, CH3-NH₂, is a weak base (pk = 3.36). Which of the following acids is sufficiently strong to protonate methylamine to an extent greater than 50% at 25°C? (pk for each acid is given) CH3CH₂-OH (-> CH3CH₂-O HIO (10.70) H₂O (15.7) H₂S (7.04) ) (15.9) Reminder: pk + pk = 14.00 (25°C) Select one: O A. H₂S only O B. HIO and H₂S O C. H₂O only O D. H₂S and H₂O OE. HIO onlyarrow_forward5. Sulfur hexafluoride, SF, has an octahedral geometry with all the F-S-F bond angles being 90°. In BrF5, the F-Br-F bond angle is 81.9°, while in XeF4, the F-Xe-F angle is 90°. Explain why 90.0 90.0⁰ 90.0 90.0⁰ 90.0 90 84.8° 84.8 84.8 84.8 90.0⁰ *90.0* 90.0⁰ 90.0⁰arrow_forward
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