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- 5. The nucleotide sequences of the DNA molecules in the figure below were obtained from four different individuals, one wild type and three mutants. Wild Type 5'-TTATCCATGATCGGATCGATCCATTAGCCGA-3' 3'-AATAGGTACTAGCCTAGCTAGGTAATCGGCT-5’ Mutant I 5'-ATCCATGATCGGATTGATCCATTAGCCGAAT-3’ 3'-TAGGTACTAGCCTAACTAGGTAATCGGCTTA-5’ Mutant II 5'-CCGTTATCCATGATCGGATAGATCCATTAGCC-3’ 3'-GGCAATAGGTACTAGCCTATCTAGGTAATCGG-5’ Mutant III 5'-CACCGTTATCCATGATCGGAACGATCCATTAGC-3’ 3'-CAGGCAATAGGTACTAGCCTTGCTAGGTAATCG-5’ a) Identify the open reading frames in each sequence of DNA and translate them into proteins. Write down the sequence of amino acids that will be obtained after translation: b) Which of the mutations above would be least likely to cause a change in the function of the protein? Why? c) Which of the mutations above would probably cause a major disruption in the function of the protein? Why?6. Using the concept of complementary base pairing, write the complementary DNA strands, with their 5' and 3' ends labeled, for each of the following DNA base sequences. a. 5' AGCTAT 3' b. 5' TTACCG 3' c. 3' GCATAA 5' d. AACTGGWhat is the complementary DNA for the following: 5' ATG CCA GCT CAT 3' A. 5'ATG CCA GCT CAT 3' B. 5'TAC GGA CTA TAC3' C. 3'TAC GGA CGA GTA5' D. 3' ATG CCA GCT CAT5'
- 1. Are each of the following mutations silent, missense, nonsense, or frameshift mutations, why? The original coding DNA strand is: 5’-ATGGGACTAGATACC-3’. 2. 5’-ATGGGTCTAGATACC-3’ 3. 5’-ATGGGACTAAGATACC-3’ 4. 5’-ATGTGACTAGATACC-3’ 5. 5’-ATGGGACTAGTTACC-3’1. What structures are these DNA strand likely to adopt in solution (assuming sufficient salt concentration to permit any hybridisation as appropriate)? Draw your answers depicting the hybridisation. a) GCC TTG AGC TTT TTT GCT CAA GGC (b) ATG ACT CTC GAG AGT CAT TTA TTA8. For each of the following DNA template strands а. 3' ТАCGGC 5b.3' ССАТТА 5' Determine: a. the base sequence of the DNA informational strands b. the base sequence of the hnRNA synthesized using the DNA template strand.
- 10. Analyse the following DNA sequences and identify and explain the anomalies you observe. Ifthere is no anomaly specify that as well. a.) 5’ A A T C T A G C T A A T T C G C A A A T T A A T C G 3’3’ T T A G A T C G U T T A A G C G T T U A A T T A G C 5’8. Which of the following is the complementary base pairing of the DNA sequence 5' ATTCGGCTTA 3'? a. 3' TAAGCCGAAT 5' b. 3' ATTCGGCTTA 5' c. 5' TAAGCCGAAT 3' d. 5' ATTCGGCTTA 3' 9. Why is DNA polymerase I used in prokaryotes? a. to repair damage to DNA base pairs b. to remove DNA sequences to form plasmids c. to fill in gaps between Okasaki fragments along the lagging strand d. to add DNA nucleotides to build new strands 10. Which set of labels is correct for the following diagram of DNA replicating? E Z A T C ATAGAC direction of replication C a. b. Alignment Paired Y C. d. Anti-parallel AATA GTT D a. X is helicase, D is ligase, and E is leading strand. b. X is gyrase, Z is leading strand, and D is single-strand bonding proteins. c. X is helicase, Y is replication fork, and D is single-strand bonding proteins. d. X is topoisomerase, Y is replication fork, and E is leading strand. 11. What term is used to describe the direction by which the backbone of DNA strands run to each other?…4. The bars in the following sequence indicate the breakpoints of a deletion. 5'-CGGGTATCTACTAAA|TTCGCACTTACGAGGATTAACATCCGATTG|TACCGAATGAGAATC-3' Which primer pair would you use to genotype for this deletion, such that all genotypes will result in a band? a. 5'-CGGGTATCTACTAAA-3' and 5'-TACCGAATGAGAATC-3' b. 5'-CGGGTATCTACTAAA-3' and 5'-GATTCTCATTCGGTA-3' с. 5'-CGGGTAТСТАСТААА-З" and 5'-CCТCGTAAGTGCGAA-3' d. 5'-CGGGTATCTACTAAA-3' and 5'-CATCCGATTGTACCG-3' e. There is no way to design a pair of primers that provide positive evidence
- A. Illustrate. Consider the given pair of homologous DNA molecules. T T' t t' Y Y' y y' L Ľ' I l' G G' g g Suppose the single strand breaks in the figure initiated an exchange of segments, and branch migration proceeded up to the L'-G' region. Following the color-coding and genotypes of the given DNA molecules,When Griffith injected mice with a combination of live rough-strain and heat-killed smooth-strain pneumococci, he discovered that (a) the mice were unharmed (b) the dead mice contained living rough-strain bacteria (c) the dead mice contained living smooth-strain bacteria (d) DNA had been transferred from the smooth-strain bacteria to the mice (e) DNA had been transferred from the rough-strain bacteria to the smooth-strain bacteria2. Tube A contains 800 µl of a DNA solution that has a concentration of 345 µg/ml. a. You transfer 0.2 ml of DNA solution from Tube A and place it into Tube B. How much total DNA is present in Tube B?