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5 What is the organic product? A. OH CH₂ (1) HgOAc₂ + H₂O (2) NaBH B. OH CH₂ C. он D. OH CH3

5 What is the organic product? A. OH CH₂ (1) HgOAc₂ + H₂O (2) NaBH B. OH CH₂ C. он D. OH CH3

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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6 Select one: 5 What is the organic product? A. OH A. carbon ring. B. C,C triple bond. A. OH B. (1) HgOAc₂ + H₂O (2) NaBH₂ OH C. C,C double bond. D. C,C single bond. CH3 C. ? он D. OH The reaction of HCI with 1-pentene produces only one product, 2-chloropentane. Why does this product form instead of 1-chloropentane? H+ and C know what the "EL-NM" rule is and dutifully comply with it. B. H+ bonds to the C-1 alkene carbon in the first step, forming the more stable carbocation, with (+) charge on C-2, followed by bonding of Cl nucleophile to positively charged C-2. C. There is less steric hindrance if Cl binds to C-2 and H+ bonds to C-1. D. Cl bonds to the C-2 alkene carbon in the first step, forming the more stable carbon anion with (-) charge on C-1, followed by bonding of H* electrophile to (-) charged C-1.
Transcribed Image Text:6 Select one: 5 What is the organic product? A. OH A. carbon ring. B. C,C triple bond. A. OH B. (1) HgOAc₂ + H₂O (2) NaBH₂ OH C. C,C double bond. D. C,C single bond. CH3 C. ? он D. OH The reaction of HCI with 1-pentene produces only one product, 2-chloropentane. Why does this product form instead of 1-chloropentane? H+ and C know what the "EL-NM" rule is and dutifully comply with it. B. H+ bonds to the C-1 alkene carbon in the first step, forming the more stable carbocation, with (+) charge on C-2, followed by bonding of Cl nucleophile to positively charged C-2. C. There is less steric hindrance if Cl binds to C-2 and H+ bonds to C-1. D. Cl bonds to the C-2 alkene carbon in the first step, forming the more stable carbon anion with (-) charge on C-1, followed by bonding of H* electrophile to (-) charged C-1.
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