Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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- please answer super super fastarrow_forwardwhy doesnt this chi square value fit the number of expected with independent assortment?arrow_forwarddd-ons Help в I U A Calibri 12 三 三1 |:三 6. Consider a guinea pig with a homozygous genotype and a white fur color phenotype. a. What is the probability this parent will produce a gamete with the dominant allele? b. What is the probability this parent will produce a gamete with the recessive allele? C. If 31 sperm cells are collected from this guinea pig, how many would you expect to have the recessive allele (as determined by sequencing the gene)? !!!arrow_forward
- 4:12 5. Set up the punnett square for each of the crosses listed below. The characteristic being studied is seed texture round seeds (dominant) and wrinkled seeds (recessive). Rr x rr Rr x Rr RR x Rr Tall: % Complete the punnett squares below using the given information. 6. A TT (tall) plant is crossed with a tt (short plant). Which trait is dominant? Give the expected probabilities for each genotype and phenotype. TT: Tt: Short: Previous % % tt: What percentage of the offspring would you expect be round? Wrinkled? ZOOM + What percentage of the offspring would you expect be round?_____ Wrinkled? What percentage of the offspring would you expect be round? Wrinkled? % 7. A hybrid tall (Tt) plant is crossed with a hybrid (Tt) plant. Give the expected probabilities for each genotype. phenotype. wvm.instructure.comarrow_forward1. The height of a wheat plant is determined by several genes. In a variety the minimum size is 12 inches and the maximum is 24 inches. 12-inch plants were crossed with 18-inch plants, and produced an 18-inch F1. The F1 was allowed to cross each other, and an F2 was obtained in which the 12 and 24 inch plants were obtained with a frequency of 2/8195. How many genes are involved in determining plant size in this variety of wheat? Select one: a. 5b. 6c. 4d. 3arrow_forwardWhat is the coefficient of coincidence and the interference? Answer in 2 decimalsarrow_forward
- In jabuticaba tree plant, Plinia cauliflora, the AA, Aa plants round fruit and aa oval fruit, the CC, Cc individuals show dark purple fruit and cc individuals are yellow; for the B locus B1B1 plants have all the fruit in their bark, B2B2 plants have fruit in the branches only and B1B2 plants have fruit in their bark and branches. A trihybrid jabuticaba having the genotype AaB1B2Cc is self-fertilized. Is there complete dominance at the B loci, yes or no? Please explain.arrow_forwardIn a series of mapping experiments, the recombination frequencies for four different linked genes of the Drosophila fly were determined, as shown in the figure. Based on this information, what is the most probable order of these genes on the chromosome? b 0 cn 90 rb 3.5 6.5 0 vg 19 9.0 16 0 b cn rb vg The numbers in the boxes are the recombination frequencies in between the genes (in percent). O b-rb-cn-vg O vg-cn-b-rb Orb-cn-vg-b b = black body cn = cinnabar eyes rb = reduced bristles vg = vestigial wings O vg-b-rb-cnarrow_forwardAnswer plsarrow_forward
- 9. Make a pedigree for each of the following situations. For each individual, write the individual's genotype (when possible) next to the individual's symbol (e.g. O xty, I Gg): a. Two parents do not have cystic fibrosis and they have a daughter with cystic fibrosis and a son who does not have cystic fibrosis. The daughter grows up and she mates with a male who does not have cystic fibrosis. Their only child is a boy and he has cystic fibrosis. b. A man with hemophilia mates with a female without hemophilia. They have one son and one daughter. The daughter has hemophilia and the son does not have hemophilia. The son grows up, and he marries and mates with a female. Their only child is a boy, and he has hemophilia.arrow_forward#9 helparrow_forwardThe drug ivacaftor has recently been developed totreat cystic fibrosis in children with the rare G551Dmutant allele of CFTR.a. Do you think that ivacaftor would be effective onlyin patients homozygous for the G551D mutation,or might it work as well in compound heterozygotes in which one copy of chromosome 7 hadG551D and the other copy a different allele ofCFTR, such as the more prevalent allele ΔF508?(The protein encoded by G551D folds up properlyand inserts into the cell membrane, but is inefficient in chloride ion transport. Ivacaftor increasesthe efficiency of G551D’s ion transport. TheΔF508 protein does not fold up properly and therefore does not get inserted into the cell membrane.)b. Why do you think ivacaftor would be more effectivein children than in older cystic fibrosis patients?c. The scientists who developed ivacaftor had a modelfor cystic fibrosis: a line of cells that grow in culture and that are homozygous for G551D. Thesecells accumulate mucus at their surfaces that…arrow_forward
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