5-4 For the given soil profile and the piezometric surfaces measured at the top of the two sand and gravel layers, determine the pore pressure and effective stress at points A, B, C, D, and E. Piezometers 2 m Ground surface 2 m Sand y = 18 kN/m3 Water table y_ y 20 kN/m3 A 4m Clay y = 18 kN/m3 •B 5 m Sand and gravel Y = 22 kN/m3 C 2 m •D 5 m Clay Y = 19 kN/m3 Sand and gravel y = 23 kN/m3 Copyright DI EIE

Q: 1- A soil profile consisting of three layers is shown in Figure below. 1. Calculate the values of o,…

A: Step 1: At D point, σ =110 x 3 + 120 x 5+118 x 2.5 = 1225 lb/ft2 U =7.5 X 62.4 =468 LB/FT2 σ' = σ –…

Q: A clay formation having a depth of 4 m. underlies a sand formation having a depth of 3, m. 16.5…

A: Depth of clay layer= 4mDepth of sand layer = 3 mUnit Weight of Sand γdry-sand = 16 kN/m3Saturated…

Q: 4- Refer to Figure below. If H1=3 ft, H2=4.5 ft, h=1.5 ft, ysa=118.9 lb/ft³, area of the tank=6.25…

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Q: 7. For the soil profile shown below, plot the variation of total stress, effective stress and pore…

A: Total stress in soil is load per unit area at any given plane in soil mass is either due to self…

Q: The soil profile shown consists of a layer of dry sand 4 m. thick which overlies a layer of clay…

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Q: The soil profile shown consists of a layer of dry sand 4 m. thick which overlies a layer of clay…

A: Effective stress is the ratio of force at contact of particles of soil to the total area. It cannot…

Q: 5. For the seepage situations shown in Figure 2, determine the effective normal stress on positions…

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Q: ,7 For the following soil element at a depth of 20 m, find: (a) The principal stresses, assuming the…

A: Normal Stress: It is defined as the stress which is induced due to the application of axial force on…

Q: Given H1 = 9.54 m., and H2 = 4.15 m. If the ground water table rises by 2.26 meters, determine the…

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Q: (b) A layer of saturated clay with 4 m thick is overlain by sand with thickness of 5 m deep, the…

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Q: 3.25 In a site consisting entirely of clays, an electric friction cone penetrometer measures the…

A: We have been given the following information,Cone resistance qc = 0.75MN/m2 at a depth of 8m.Water…

Q: Dry Sand Clay Groundwater, 4 Table 42-

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Q: Refer to the soil profile shown. Given H1 = 9.89 m., and H2 = 5.80 m. If the ground water table…

A: Formulae used      Unit weight of soil                     (G + es)× Yw/(1+e)    For dry sand ,s = 0…

Q: Plot the distribution of total stress, effective stress, and pore- water pressure with depth for the…

A: Following is the given soil profile:   Given: For soil up to the depth of 4.5 m (A-B): Void ratio,…

Q: Question 1 A 5-m depth of sand overlies a 6-m layer of clay, the water table being at the surface.…

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Q: Given soil formation and the corresponding properties of soil in each layer. To consolidate the…

A: step 1-

Q: The soil profile shown consists of a layer of dry sand 4 m. thick which overlies a layer of clay…

A:

Q: 2 m 5 m 2 m Silt Clay 3 m A Sand under artesian pressure Bedrock 7. 6 m Soil profile is given in…

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Q: 4.5 meters of clay underlain by 4.5 meters of sand. Water table is 3 meters from the ground level.…

A: Effective stress is the difference between total stress (σ) and the pore water pressure (u). Total…

Q: Plot the variation in the effective stress (o') for the given soil profile. Plot your answer here…

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Q: Problem1) According to the given soil profile, fill the table and plot the distribution of vertical…

A: Given data- Specific gravity Gs=2.7

Q: Another method of determining the capillary rise in a soil is to use Hazen's capillary formula. The…

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Q: Question attached

A: Given data- Effective dia Do =0.01 mm = 0.001 cm

Q: 4. A 10 m thick layer of shift, saturated clay is underlain by a layer of sand. The sand is under…

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Q: Q.4) Detemine and plot the variations of total and vertical stresses and pore water pressure with…

A: Given data- To find- Total, effective, and pore water pressure.

Q: Determine values of total stress, pore water pressure and effective stress at each soil layer then…

A: Calculating the total stress: σ=γd1×h1+γt1×h2+γt2×h3   =13.1×2+18×2.5+19.8×4.5   =160.3 KN/m2

Q: Q.4) Detemine and plot the variations of total and vertical stresses and pore water pressure with…

A: calculating total stress and pore water pressure then plotting it

Q: From the given soil formation of the soil with the following properties is shown in the figure.…

A: Given data in question  Unit weight  Depths Clay and sand layer Loading Square footing  To find out…

Q: Q: For the soil profile shown in figure, 1- Determine the total stress, effective stress, and pore…

A: Finding out total stress, effective stress, pore water pressure.

Q: A deposit of clay underlain a 4.5 m thick sand. Degree of saturation of sand is 37% and void ratio…

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Q: For soil profile and uniformly distributed loaded area shown below, find the increases in the…

A: Given data in question  Unit weights Depths  Cross section dimensions of circle and rectangle. To…

Q: The soil profile shown consists of a layer of dry sand 4 m. thick which overlies a layer of clay…

A: A soil profile is given as shown in the figure above in which 2 soils are given, one is dry sand of…

Q: show the variation beneath the edge of the loaded area.

A: Consider the following equation : σz=q1-11+r2232 Here r= 5ft Plot the variation of the vertical…

Q: Dry sand 6m Ydry = 16.5 kN/m³ B Groundwater table Saturated sand Ysat = 19.25 kN/m 13m Dry sand…

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Q: 5m 3m 2m N.G.L Gs=2.67, e = 0.78 Sand 3 y(sat.) = 18KN/m ³ Silty Clay 20KN Ysat. m3 Gravel

A: step 1-

Q: 17. Refer to the soil profile shown. Given H1 = 9.29 m., and H2 = 5.67 m. If the ground water table…

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Q: The arrangement of soil layers are as shown below. Lower layer of sand is under artesian pressure.…

A: Given data,Amount by which piezometric head in lower layer of sand rises above water table

Q: 7. For the soil element shown, determine the following: a. Maximum and minimum principal stresses b.…

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Q: GS 1.87 Vm GWT Sand Yar QI: Plot the variation of the total vertical stress, effective stress, and…

A: This question belong to soil mechanics  Take unit weight of water = 1 t/cu.m

Q: Refer to the soil profile shown. Given H1 = 9.80 m., and H2 = 5.17 m. If the ground water table…

A: To Find :- change in effective stress at bottom of clay layer due to rise in water table. Consider…

Q: 6. From the given soil profile, the groundwater table is located 2m below the ground level. (See…

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Q: The soil in a deposit underlying an area where a level ground surface exists has a unit weight of 22…

A: Given data: Unit weight of soil = 22 kN/m3. Depth = 5m Lateral pressure = 0.5 vertical pressure.

Q: 7.2 Compute the total vertical stress o, pore water pressure u, and then the effective vertical…

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Q: Yeat s17 KN/3 embankment sand Yset =18 KN/m} Yot =17 JeNm? clay ym 5m

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Q: R-1: For the following soil system determine the effective stress and pore-water pressure at the…

A: Saturated unit weightγsat=18 kN/m3 Unit weight of water γw=10 kN/m3

Q: (c). The magnitude of stresses have been applied on soil element where Normal vertical stress is 120…

A: Normal stresses are given and we have to find the stresses on the inclined plane given in question…

Q: The soil profile shown consists of a layer of dry sand 4 m. thick which overlies a layer of clay…

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Q: A. Compute the effective stress at the bottom of the clay. B. If the water table rises to the level…

A: Given data in question.  Unit weights Depths Water table  To find out  Effective stress at bottom

Q: Calculate the effective stress before drawdown in the soil at the depth of soil and depth of water…

A: Given: The depth of soil is 30 ft. The depth of water is 25 ft. The unit weight of soil is 120…

Q: A 10-m-thick layer of stiff saturated clay is underlain by a layer of sand (Figure 9.28). The sand…

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Methods to Determine Vertical Stress

The load applied to the soil is transferred to the underground. The presence of water at soil pores and solid grains above the soil are the primary components that are responsible for the effective load transfer. Due to the load acting, the internal component of the soil or the underground formations undergoes deformations or a tectonic shift. The amount of deformation depends upon the amount of load acting on the soil surface, which indeed, depends on the weight of everything present above the soil. Due to this, the underground soil element develops internal stresses which try to resist the tectonic changes.