5 3-j4 2 10 L90° 12 15 Lo 20/0° Za = 5 ohms Zb= 3-j4 ohms Zc= 2 ohms Zd= 12 ohms V1= 20 angle 0 V2 = 10 angle 90 V3 = 15 angle 0 1. Same figure, solve the current at branch Zb, Vth, Rth, Isc, Rn using Thevenin's and Norton's theorem.

5 3-j4 2 10 L90° 12 15 Lo 20/0° Za = 5 ohms Zb= 3-j4 ohms Zc= 2 ohms Zd= 12 ohms V1= 20 angle 0 V2 = 10 angle 90 V3 = 15 angle 0 1. Same figure, solve the current at branch Zb, Vth, Rth, Isc, Rn using Thevenin's and Norton's theorem.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

Norton Theorem

In the current circuit law, the Norton theorem (also known as the Mayer-Norton theorem) is a simplification that can be applied to networks generated by a constant line of opposition, power sources, and current assets. In two network terminals, it can be switched on with a current supply and single resistor respectively.

Question

Thevenin's and Norton

12
20/0⁰
15/0%
Za = 5 ohms
Zb= 3-j4 ohms
Zc= 2 ohms
Zd = 12 ohms
V1= 20 angle 0
V2 = 10 angle 90
V3 = 15 angle 0
1. Same figure, solve the current at branch Zb, Vth, Rth, Isc, Rn using Thevenin's and Norton's
theorem.
Solve neatly and correctly. Round off your solutions to 3 decimal places. Box your final answers.
5
3-j4
2
10 L90°

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