Homework Help is Here – Start Your Trial Now!
Science
Chemistry
5 2-Bromobutane, CH3CH₂CHBrCH3, can be prepared by three different methods. The relative molecular mass, M,, of 2-bromobutane is 136.9. (a) 2-Bromobutane can be prepared by reacting butane with bromine (Reaction 5.1). CH₂CH₂CH₂CH₂ + Br₂ → CH₂CH₂CHBrCH3 + HBr Reaction 5.1 The reaction is initiated by the formation of bromine radicals from bromine. (i) State the conditions for the formation of bromine radicals from bromine. (ii) Write two equations for the propagation steps in the mechanism for Reaction 5.1. Use structural formulae for organic species and dots (•) for unpaired electrons on radicals. CH3CH₂CH₂CH3 (iii) The yield of CH3CH₂CHBRCH3 is only 30%. Suggest two reasons why the yield of CH3CH₂CHBrCH3 is so low. 1 2

5 2-Bromobutane, CH3CH₂CHBrCH3, can be prepared by three different methods. The relative molecular mass, M,, of 2-bromobutane is 136.9. (a) 2-Bromobutane can be prepared by reacting butane with bromine (Reaction 5.1). CH₂CH₂CH₂CH₂ + Br₂ → CH₂CH₂CHBrCH3 + HBr Reaction 5.1 The reaction is initiated by the formation of bromine radicals from bromine. (i) State the conditions for the formation of bromine radicals from bromine. (ii) Write two equations for the propagation steps in the mechanism for Reaction 5.1. Use structural formulae for organic species and dots (•) for unpaired electrons on radicals. CH3CH₂CH₂CH3 (iii) The yield of CH3CH₂CHBRCH3 is only 30%. Suggest two reasons why the yield of CH3CH₂CHBrCH3 is so low. 1 2

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
See similar textbooks
icon
Related questions
Question
Question 5a pleaseee
5 2-Bromobutane, CH₂CH₂CHBRCH3, can be prepared by three different methods. The relative molecular mass, M₁, of 2-bromobutane is 136.9. (a) 2-Bromobutane can be prepared by reacting butane with bromine (Reaction 5.1). CH₂CH₂CH₂CH₂ + Br₂ → CH₂CH₂CHBrCH3 + HBr Reaction 5.1 The reaction is initiated by the formation of bromine radicals from bromine. (i) State the conditions for the formation of bromine radicals from bromine. (ii) Write two equations for the propagation steps in the mechanism for Reaction 5.1. Use structural formulae for organic species and dots (•) for unpaired electrons on radicals. CH3CH₂CH₂CH3 (iii) The yield of CH3CH₂CHBCH3 is only 30%. Suggest two reasons why the yield of CH3CH₂CHBCH3 is so low. 1 2 (b) 2-Bromobutane can also be prepared by reacting but-2-ene, CH₂CH=CHCH3, with hydrogen bromide, HBr (Reaction 5.2). CH₂CH=CHCH3 + HBr → CH3CH₂CHBrCH3 Explain, in terms of atom economy, why Reaction 5.2 is more sustainable than Reaction 5.1. Include calculations to justify your answer. Reaction 5.2
Transcribed Image Text:5 2-Bromobutane, CH₂CH₂CHBRCH3, can be prepared by three different methods. The relative molecular mass, M₁, of 2-bromobutane is 136.9. (a) 2-Bromobutane can be prepared by reacting butane with bromine (Reaction 5.1). CH₂CH₂CH₂CH₂ + Br₂ → CH₂CH₂CHBrCH3 + HBr Reaction 5.1 The reaction is initiated by the formation of bromine radicals from bromine. (i) State the conditions for the formation of bromine radicals from bromine. (ii) Write two equations for the propagation steps in the mechanism for Reaction 5.1. Use structural formulae for organic species and dots (•) for unpaired electrons on radicals. CH3CH₂CH₂CH3 (iii) The yield of CH3CH₂CHBCH3 is only 30%. Suggest two reasons why the yield of CH3CH₂CHBCH3 is so low. 1 2 (b) 2-Bromobutane can also be prepared by reacting but-2-ene, CH₂CH=CHCH3, with hydrogen bromide, HBr (Reaction 5.2). CH₂CH=CHCH3 + HBr → CH3CH₂CHBrCH3 Explain, in terms of atom economy, why Reaction 5.2 is more sustainable than Reaction 5.1. Include calculations to justify your answer. Reaction 5.2
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Alkanes and Cycloalkanes
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY
SEE MORE TEXTBOOKS