(4%) Problem 4: AAV = 1.5 V battery loses E = 5.5 J of energy each day (t= 24 hrs) powering a cell phone.Randomized VariablesAV = 1.5 VE = 5.5 J50% Part (a) Input an expression for the average current, I, supplied to the phone.50% Part (b) What is the current, in amperes?

Given: ∆V=1.5 V Energy loss, E=5.5 J Time, t=24 hrs To find (a) write an expression for current.…

(4%) Problem 4: AAV =1.5 V battery loses E = 5.5 J of energy each day (t 24 hrs) powering a cell phone. Randomized Variables AV - 1.5 V E = 5.5 J A 50% Part (a) Input an expression for the average current, I, supplied to the phone. 50% Part (b) What is the current, in amperes? I=

(4%) Problem 4: AAV =1.5 V battery loses E = 5.5 J of energy each day (t 24 hrs) powering a cell phone. Randomized Variables AV - 1.5 V E = 5.5 J A 50% Part (a) Input an expression for the average current, I, supplied to the phone. 50% Part (b) What is the current, in amperes? I=

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter9: Current And Resistance

Section: Chapter Questions

Problem 29P: The current of an election beam has a measuredcurrent of I=50.00A with a radius of 1.00 mm2. What is...

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Concept explainers

Ohm's law

Ohm’s law is a prominent concept in physics and electronics. It gives the relation between the current and the voltage. It is used to analyze and construct electrical circuits. Ohm's law states that the voltage across a conductor is directly proportional to the current flowing through it.

Path of Least Resistance

In a series of alternate pathways, the direction of least resistance is the actual or metaphorical route that offers the least resistance to forwarding motion by a given individual or body.

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(4%) Problem 4: AAV = 1.5 V battery loses E = 5.5 J of energy each day (t= 24 hrs) powering a cell phone.
Randomized Variables
AV = 1.5 V
E = 5.5 J
50% Part (a) Input an expression for the average current, I, supplied to the phone.
50% Part (b) What is the current, in amperes?

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