(a) Suppose υbe(t) = 0.005 sin 2000πt V in the bipolar amplifier as shown . Write expressions for υbe(t), vce(t), and υCE(t). (b) What is the maximum value of IC that corresponds to the active region of operation? 4.0 mA+10 VUCE()6.7 VRcVRE = 0.717 V3.3 k23.0 mAB= 30 μΑ%3DVce (1)ic3.3 VVBE = 0.708 V2.0 mAVbe(1)IR = 20 µAUCE4BE)VBE = 0.700 V3= 15 μΑVBE = 0.692 V15-10 μΑ0.708 VQ-pointUpeU BE1.0 mA0.700 V0.700 VVBELoad line%3D0,692 V -OV4 V10 V12 VCollector-emitter voltage(a)(b)Figure 13.1 (a) BJT biased in the active region by the voltage source VBE. A small sinusoidal signal voltage v, is appliedin series with VBE and generates a similar but larger amplitude waveform at the collector; (b) load-line, Q-point, and signalsfor circuit of Fig. 13.1(a).isCollector curre nt

Given Calculating base to emitter voltage

Answered: 4.0 mA +10 V UCE() 6.7 V Rc VRE = 0.717…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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(a) Suppose υ_be(t) = 0.005 sin 2000πt V in the bipolar amplifier as shown . Write expressions for υ_be(t), vce(t), and υ_CE(t). (b) What is the maximum value of I_C that corresponds to the active region of operation?

4.0 mA
+10 V
UCE()
6.7 V
Rc
VRE = 0.717 V
3.3 k2
3.0 mA
B= 30 μΑ
%3D
Vce (1)
ic
3.3 V
VBE = 0.708 V
2.0 mA
Vbe(1)
IR = 20 µA
UCE
4BE)
VBE = 0.700 V
3= 15 μΑ
VBE = 0.692 V
15-10 μΑ
0.708 V
Q-point
Upe
U BE
1.0 mA
0.700 V
0.700 V
VBE
Load line
%3D
0,692 V -
OV
4 V
10 V
12 V
Collector-emitter voltage
(a)
(b)
Figure 13.1 (a) BJT biased in the active region by the voltage source VBE. A small sinusoidal signal voltage v, is applied
in series with VBE and generates a similar but larger amplitude waveform at the collector; (b) load-line, Q-point, and signals
for circuit of Fig. 13.1(a).
is
Collector curre nt

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