4.0 kN 1.5 kN/m |A В 1.0 m→-1.0 m→* 2.0 m

part a and b

pls reply asaap!! A wooden beam AB supporting two concentrated loads P has a rectangular cross section of width b = 100 mm and height h = 150 mm. The distance from each end of the beam to the nearest load is a = 0.5 m. The span of the beam is 5 m. Calculate for the total length of the segment of the beam, in meters, that is subjected to a constant bending moment.

Part 1 For the simply supported beam subjected to the loading shown, derive equations for the shear force Vand the bending moment M for any location in the beam. (Place the origin at point A.) Let a-14.0 ft, b-5.5 ft, c- 8.0 ft, w - 9 kips/ft and M - 260 kip-ft. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. Calculate the reaction forces Ay and Cy acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax - 0, it has been omitted from the free-body diagram.) - 0, B Answers: Ay- kips kips Part 2 Determine the shear force acting at each of the following locations: (a) x - 0+ ft (i.e., just to the right of support A) (b) x - 14.0 ft (i,e., at point B) (c) x - 19.5- ft (i.e., just to the left of the support C) (d) x - 19.5+ ft (i.e., just to the right of the support (C) (e) x - 26.5 ft…