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4. What is the equilibrium constant of this reaction at 25 °C? 5. After 56.0 hours at 1.04 A, how many moles of electrons have been used in this reaction? 6. Predict the sign of the entropy (ASrxn) for this electrochemical reaction. Explain your reasoning.

4. What is the equilibrium constant of this reaction at 25 °C? 5. After 56.0 hours at 1.04 A, how many moles of electrons have been used in this reaction? 6. Predict the sign of the entropy (ASrxn) for this electrochemical reaction. Explain your reasoning.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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1. Find the overall reaction that will be occurring between the H₂B03/ B and Bio+ / Bi half cells in acidic conditions. 2. What is the standard cell voltage of this electrochemical cell? 3. What is the standard free energy of this reaction? 4. What is the equilibrium constant of this reaction at 25 °C? 5. After 56.0 hours at 1.04 A, how many moles of electrons have been used in this reaction? 6. Predict the sign of the entropy (ASrxn) for this electrochemical reaction. Explain your reasoning.
Transcribed Image Text:1. Find the overall reaction that will be occurring between the H₂B03/ B and Bio+ / Bi half cells in acidic conditions. 2. What is the standard cell voltage of this electrochemical cell? 3. What is the standard free energy of this reaction? 4. What is the equilibrium constant of this reaction at 25 °C? 5. After 56.0 hours at 1.04 A, how many moles of electrons have been used in this reaction? 6. Predict the sign of the entropy (ASrxn) for this electrochemical reaction. Explain your reasoning.
x kb = 1.38 × 10-23/ K 1 mL = 1 cm³ C mol 1 atm = 760 torr F = 9.648 x 104 Reaction H₂B03 (aq) / B (s) Bi0+ (aq) / Bi (s) R = 8.3145 Ered (V) -0.8698 0.320 J mol. K A 14=1² 1V=1/2
Transcribed Image Text:x kb = 1.38 × 10-23/ K 1 mL = 1 cm³ C mol 1 atm = 760 torr F = 9.648 x 104 Reaction H₂B03 (aq) / B (s) Bi0+ (aq) / Bi (s) R = 8.3145 Ered (V) -0.8698 0.320 J mol. K A 14=1² 1V=1/2
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