2- 185.0 mL of .12 M C2H5NH2 with 285.0 mL of 0.21 M C2H5NH3CI Kb(C2H5NH2) = 5.6×10^-4 Express your answer using two decimal places. pH = ?

Fundamentals Of Analytical Chemistry
9th Edition
ISBN:9781285640686
Author:Skoog
Publisher:Skoog
Chapter20: Applications Of Oxidation/reduction Titrations
Section: Chapter Questions
Problem 20.6QAP
icon
Related questions
Question
2-
185.0 mL of .12 M C2H5NH2 with 285.0 mL
of 0.21 M C2H5NH3CI
Kb(C2H5NH2) = 5.6×10^-4
Express your answer using two decimal
places.
pH = ?
Transcribed Image Text:2- 185.0 mL of .12 M C2H5NH2 with 285.0 mL of 0.21 M C2H5NH3CI Kb(C2H5NH2) = 5.6×10^-4 Express your answer using two decimal places. pH = ?
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Knowledge Booster
Acid-Base Titrations
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Fundamentals Of Analytical Chemistry
Fundamentals Of Analytical Chemistry
Chemistry
ISBN:
9781285640686
Author:
Skoog
Publisher:
Cengage