State hypothesisDefine test, one or 2 sided?Test assumptions (equal variance, normality)State test statistic (t, F, Chi-square)State critical value (1 or 2 sided, degrees of freedom) example: f crit (1, 3, 20)State conclusions.You can use Excel or STATA as an aid to perform the tests, but you should be "in control" of all the steps. Ifapplicable, include STATA outputs, or Excel spreadsheets, in your submission. 4. The following is the distribution of the daily emission of sulfur oxides by anindustrial plant. As can easily be verified, the mean of the distribution is 18.85and its standard deviation is s=5.55. To test the null hypothesis that these dataconstitute a random sample from a normal population, proceed with the followingsteps:Tons of Sulfur Freq.5.0-8.999.0-12.9913.0-16.9917.0-20.9921.0-24.9925.0-28.9929.0-32.99C.310142517a. Find the probabilities that a random variable having the normal distributionwith u-18.85 and 0-5.5 will take on a value less than 8.95, between 8.95 and12.95, between 12.95 and 16.95, between 16.95 and 20.95, between 20.995and 24.95, between 24.95 and 28.95, and greater than 28.95.b. Changing the first and last classes of the distribution to "8.95 or less" and "28.95 or more" find the expectednormal curve frequencies corresponding to the seven classes of the distribution by multiplying theprobabilities obtained in part (a) by the total frequency of 80.Test at the 0.05 level of significance whether the given data may be looked upon as a random sample from anormal distribution. Recall: expected values for any cell cannot be below 5; combine cells if needed.92

To find the probabilities, we can use the standard normal distribution and standardize each value…

Answered: 4. The following is the distribution of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The life of a butterfly is normally distributed with a mean of 50 days. You took a random sample of 25 such butterflies. The mean life for this sample is 47 days a standard deviation of 3 days. At α = 0.05. a. Test to see if the average life of a butterfly is different from 50 days. b. Your friend believes that the life of a butterfly is less than 50 days. Is she correct?
Biological oxygen demand (BOD) is a pollution index that is monitored in the treated effluent of paper mills. A certain paper mill has taken 31 samples over the past 3 months. The mean and standard deviation for the sample data are 3.42 and 0.728 ppm respectively. The mill would like to see if this sample indicates that the true average BOD in their treated effluent exceeds the targeted 3.00 ppm. Let ? = 0.05. A) The test statistic, (ttest), for this data set is: Note: Round your answer to the nearest hundredth.B) The p-value is: C) The statistical decision and corresponding English interpretation for this study are: Fail to reject Ha: conclude that the true BOD in treated effluent exceeds 3 ppmFail to reject Ho: we cannot conclude that the true BOD in treated effluent exceeds 3 ppm Reject Ha: we cannot conclude that the true BOD in treated effluent exceeds 3 ppmReject Ho: conclude that the true BOD in treated effluent exceeds 3 ppm
2. 1 (your instructor) am 66" tall. Assume that the population mean for adult males is 70" with a standard deviation of 2.5". What is the percentile of my height for adult males
Assume that you have been provided the following information for a sample of cars The covariance between weight and miles per gallon is equal to -4.9 pound-miles. The standard deviation of the cars' mileages is 7.75. The standard deviation of the cars' weights is 0.94. Estimate the correlation coefficient to the first decimal place.
A person's body mass index (BMI) is computed by dividing the weight (kg) by the square of height (m). The accompanying table contains the BMI statistics for random samples of males and females. Assume that the two samples are independent simple random samples selected from normally distributedpopulations, and do not assume that the population standard deviations are equal. Let population 1 be females. Female BMI: n=69 x=29.14 s=7.41 Male BMI: n=79 x=28.18 s=5.24 The test statistic is The P-value is Construct a confidence interval appropriate for testing the claim in part (a). The ___% confidence interval estimate is ___<μ1−μ2<___.
There are many situations in which we want to compare means from populations having standard deviations that are equal. This method applies even if the standard deviations are known to be only approximately equal. Consider a report regarding average incidence of fox rabies in two regions. For region I, n1 = 16, x1 ≈ 4.73, and s1 = 2.84 and for region II, n2 = 15, x2 ≈ 3.93, and s2 = 2.45. The two sample standard deviations are sufficiently close that we can assume ?1 = ?2. Use the method of pooled standard deviation to consider the report, testing if there is a difference in population mean average incidence of rabies at the 5% level of significance. (Round your answer to three decimal places.) t =
Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 7.9 parts/million (ppm). A researcher believes that the current ozone level is at an excess level. The mean of 24 samples is 8.1 ppm with a variance of 0.25. Does the data support the claim at the 0.1 level? Assume the population distribution is approximately normal. Step 5 of 5: Make the decision to reject or fail to reject the null hypothesis.
You suspect that people living in urban areas produce on average more garbage (X)than those living in rural areas (Y). To verify this opinion, you draw two samples and collect information on the amount of garbage produced in a month (measured in kilos). The first sample, made of 8 subjects living in an urban area, provides a sample mean equal to 40.5 and a sample standard deviation equal to 5.6; in the second sample, made of 10 subjects living in rural areas, the sample mean is 35.6 and the sample standard deviation is 7.5. It is assumed that the two populations are normal with the same unknown variance.Test the null hypothesis that the two population means are equal against a one-sided alternative according to which people living in urban areas produce on average more garbage than those living in rural areas. Use a 1% significance level.
Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 4.6 parts/million (ppm). A researcher believes that the current ozone level is at an excess level. The mean of 14 samples is 4.9 ppm with a variance of 1.2 Does the data support the claim at the 0.01 level? Assume the population distribution is approximately normal. Step 2 of 5 : Find the value of the test statistic. Round your answer to three decimal places.
3.1. Suppose that the height of the women is a normal variable with a mean of 1.62 meters (m) and a standard deviation of 24 centimeters. Calculate the percentage of women who measures (a) more than 1.70 m. (b) between 1.66 and 1.58 m. (c) less than 1.50 m. d) between 1.60 and 1.63 m.
A Moving to another question will save this response. Question 1 Consider a sample with a mean of 30 and a standard deviation of 2.5. Use Chebyshev's theorem to determine the percentage of the data within the ranges from 23 to 37. O a. 61% O b. 75% O c. 87% Od. 83%
For a population with a population mean = 60 and a population standard deviation = 9, find the score (X value) that corresponds to each of the following z - scores. A. z-= -1.00 B. z- =+0.70

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