4. Give the products for the reactions below: 1. Hg(OAc)2 / H20 1. ВНз a 2. NaOH, H2O2 2. NABH4

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Chapter1: Chemical Foundations
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**Question 4: Give the products for the reactions below:**

**Reaction a:**

- Starting Material: 2-methylpropene
- Reagents:
  1. Hg(OAc)₂ (Mercuric acetate) / H₂O
  2. NaBH₄ (Sodium borohydride)

**Reaction b:**

- Starting Material: 2-methylpropene
- Reagents:
  1. BH₃ (Borane)
  2. NaOH, H₂O₂ (Sodium hydroxide and Hydrogen peroxide)

**Explanation for an Educational Website:**

The image illustrates two chemical reactions involving an alkene, specifically 2-methylpropene, undergoing hydration. 

**Reaction a:** This is an oxymercuration-demercuration reaction. Initially, mercuric acetate and water add across the double bond in an anti-Markovnikov fashion. Then, sodium borohydride is used for the reduction step, removing mercury and forming the alcohol.

**Reaction b:** This is hydroboration-oxidation. Borane adds to the alkene in an anti-Markovnikov manner, followed by oxidation with sodium hydroxide and hydrogen peroxide, resulting in the alcohol.

Both reactions involve the conversion of an alkene into an alcohol, but they differ in regioselectivity and stereochemistry.
Transcribed Image Text:**Question 4: Give the products for the reactions below:** **Reaction a:** - Starting Material: 2-methylpropene - Reagents: 1. Hg(OAc)₂ (Mercuric acetate) / H₂O 2. NaBH₄ (Sodium borohydride) **Reaction b:** - Starting Material: 2-methylpropene - Reagents: 1. BH₃ (Borane) 2. NaOH, H₂O₂ (Sodium hydroxide and Hydrogen peroxide) **Explanation for an Educational Website:** The image illustrates two chemical reactions involving an alkene, specifically 2-methylpropene, undergoing hydration. **Reaction a:** This is an oxymercuration-demercuration reaction. Initially, mercuric acetate and water add across the double bond in an anti-Markovnikov fashion. Then, sodium borohydride is used for the reduction step, removing mercury and forming the alcohol. **Reaction b:** This is hydroboration-oxidation. Borane adds to the alkene in an anti-Markovnikov manner, followed by oxidation with sodium hydroxide and hydrogen peroxide, resulting in the alcohol. Both reactions involve the conversion of an alkene into an alcohol, but they differ in regioselectivity and stereochemistry.
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