4. Considering sag rods and tie rods at midspan, what is the required diameter of sag rods in mm? (rounded value) A 20m Fink Truss are spaced at 'S' meters o.c. the purlins are made up of C10X20 sections and are spaced 1.1967m on centers. The truss has a height of 4m. Roof LL is 'RLL' N/m2 of roof surface and roof covering is assumed to be 'RDL' N/m2 of roof surface. Determine whether the purlins are adequate to carry such loadings. Fy = 248 MPa. C10X20 properties: w=29.76kg/m, A=3787.09mm2, Ix=32.84x106mm4, Iy=1.17x106mm4, Zx=317.91x103mm3, Sx=258.92x103mm3, Zy=44.25x103mm3, Sy=21.47x103mm3 S (m) RLL (N/m^2) RDL (N/m^2) 6.00 900 900

4. Considering sag rods and tie rods at midspan, what is the required diameter of sag rods in mm? (rounded value) A 20m Fink Truss are spaced at 'S' meters o.c. the purlins are made up of C10X20 sections and are spaced 1.1967m on centers. The truss has a height of 4m. Roof LL is 'RLL' N/m2 of roof surface and roof covering is assumed to be 'RDL' N/m2 of roof surface. Determine whether the purlins are adequate to carry such loadings. Fy = 248 MPa. C10X20 properties: w=29.76kg/m, A=3787.09mm2, Ix=32.84x106mm4, Iy=1.17x106mm4, Zx=317.91x103mm3, Sx=258.92x103mm3, Zy=44.25x103mm3, Sy=21.47x103mm3 S (m) RLL (N/m^2) RDL (N/m^2) 6.00 900 900

Steel Design (Activate Learning with these NEW titles from Engineering!)

6th Edition

ISBN:9781337094740

Author:Segui, William T.

Publisher:Segui, William T.

Chapter3: Tension Members

Section: Chapter Questions

Problem 3.8.3P

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Example 3.15 FIGURE 3.32 Fink trusses spaced at 20 feet on centers support W6 x 12 purlins, as shown in Figure 3.32a. The purlins are supported at their midpoints by sag rods. Use A36 steel and design the sag rods and the tie rod at the ridge for the following service loads. Metal deck: Built-up roof: Snow: Purlin weight: 46.6' 2 @ 12' = 24' 4.679 k 46.6 18.17k (b) 2 psf 5 psf 45 18 psf of horizontal projection of the roof surface 12 pounds per foot (lb/ft) of length 112 42' 90' (a) P P 2@ 12' = 24' F R R 12 (c) 45 3' 3' 3' 3' 12' 4.679 k 4.679k
Which joint would be the best place to start your analysis of the truss shown? D 8k 12 k O a. F O b. D O c. B O d.c E 15 ft- + 15 ft- B 24 k +15 ft- 2+15+ -15 ft- T 8 ft EL
ASSIGNMENT #6 CASE 2 Purlin Design The figure shown has trusses 5.5m apart with midpoint sag rods and Purlins spaced 2.5m on center. The roof truss is inclined 1 vertical to 2 horizontal. The weight of roofing materials is 0.8 kPa, wind load is 0.7 kPa perpendicular to the roof surface, minimum roof live load is 0.6 kPa. Design a channel section of steel Fy = 345 mPa, for the purlins. Use LRFD and ASD of NSCP 2015.
Which of the following best gives the purlin load wuy? See loaded purlin. The figure shown has trusses 6m apart with midpoint sag rods and Purlins C150x12.5 spaced 2.5m on center. The roof truss is inclined 1 vertical to 2 horizontal. The weight of roofing materials is 0.9 kPa (includes self wt.), wind load is 0.8 kPa perpendicular to the roof surface, minimum roof live load is 0.6 kPa. Consider the roofing to provide full lateral support of the purlins. Fy = 345 mPa. Use the NSCP 2015 specifications. 2. 5m 2.5m 2. 5m roofing TRUSS TOP CHORD Wuy, Truss Spacing = 6m Wux 1 Purlins C150x12.5 Purlin Load Wt kN/m mm^2 mm C150x12.5 0.12 11400 12.7 152 5.1 d tw by SECTION Ix Sx rx ly sy Zy ry Zx mm mm mm^4 mm^3 mm mm^4 mm^3 mm mm^3 mm^3 mm mm 48 8.7 143 1100 112 48.4 378 65.2 1230 574 O 4.35 kN/m 5.56 kN/m O 25.02 kN.m
8. Considering sag rods and tie rods at third points, what is the required diameter of sag rods? (rounded value) A 20m Fink Truss are spaced at 'S' meters o.c. the purlins are made up of C10X20 sections and are spaced 1.1967m on centers. The truss has a height of 4m. Roof LL is 'RLL' N/m2 of roof surface and roof covering is assumed to be 'RDL' N/m2 of roof surface. Determine whether the purlins are adequate to carry such loadings. Fy = 248 MPa. C10X20 properties: w=29.76kg/m, A=3787.09mm2, Ix=32.84x106mm4, Iy=1.17x106mm4, Zx=317.91x103mm3, Sx=258.92x103mm3, Zy=44.25x103mm3, Sy=21.47x103mm3 S (m) RLL (N/m^2) RDL (N/m^2) 6.00 900 900
Which of the following best gives the purlin load wuy? See loaded purlin. The figure shown has trusses 6m apart with midpoint sag rods and Purlins C150x12.5 spaced 2.5m on center. The roof truss is inclined 1 vertical to 2 horizontal. The weight of roofing materials is 0.9 kPa (includes self wt.), wind load is 0.8 kPa perpendicular to the roof surface, minimum roof live load is 0.6 kPa. Consider the roofing to provide full lateral support of the purlins. F, = 345 mPa. Use the NSCP 2015 specifications. 2. 5m 2.5m 2. 5m roofing Wuy TRUSS TOP CHORD Truss Spacing = 6m Wux Purlins C150x12.5 Purlin Load Wt A kN/m mm^2 mm C150x12.5 0.12 11400 12.7 152 5.1 SECTION dtw by Ix Sx rx ly mm mm^4 mm^3 mm mm^4 mm^3 mm mm^3 mm^3 48 8.7 143 1100 112 48.4 378 65.2 1230 574 Sy ry Zx| Zy mm mm mm O 4.35 kN/m 5.56 kN/m O 25.02 kN.m
Select all zero-force members in the truss shown below. Check the box for zero- force members 3m 12 m, 8 @ 1.5 m O DE LK EP OHF O BC O BM O EF O OM O CD O BN LO O DK FI O co O O O O O O 0 0 O 0
Identify the zero force members in the truss shown. (Enter your answers as a comma-separated list.) E F A
Part A - Identifying zero-force members Consider the truss shown below. Identify the zero-force members. A P_ E B D Check all that apply. • View Available Hint(s) ВС АВ ВЕ AE DE CD O CE Submit
7:YE I %AV . * O ASSIGNMENT (H... ASSIGNMENT Using method of sections, determine the force in members identified (CD, CI, El and HI) for the trusses shown 24 kN 24 kN Io to B E 1.5 m A J IH 4 @ 2m
50 kN 50 kN 100 kN Sm 4m 3m From the given truss, which member has an internal force of 50 kN COMPRESSION ? AD AC CD BD
The figure shows a roof truss and the detail of connection at joint I. The allowable stresses are 70 MPa for shear and 120 MPa for bearing. How many 20-mm diameter rivets are required to fasten member IG to the gusset plate? What is the required area for member AI if the allowable axial stress is 180 MPa. D 30 kN 70 kN 2 m 12 mm-thick gusset plate 10 -mm-chick angle 2m 15 m -15 m-15 m† 15 m - 8 mm-thick angle IG 80 kN 120 kN 50 kN IH 6. nIG due to shear due to bearing nIG = Therefore, use nIG AAI = mm?