Q5/ A differential leveling are began at B.M1 to B.M2 [in 4th degree leveling process], determine the error of closure and maximum acceptable error, then correct the elevation of all points if the error are acceptable, use the data in the table below. Point B.M 1 A T.P1 B B.M2 Distance (m) 300.... **** **** **** 150 280 **** **** R.L 31.257 31.801 30.773 29.624 30.259 Correction Corrected R.L R.L (Fixed) 30.270

Q5/ A differential leveling are began at B.M1 to B.M2 [in 4th degree leveling process], determine the error of closure and maximum acceptable error, then correct the elevation of all points if the error are acceptable, use the data in the table below. Point B.M 1 A T.P1 B B.M2 Distance (m) 300.... 150 280 R.L 31.257 31.801 30.773 29.624 30.259 Correction Corrected R.L R.L (Fixed) 30.270

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: In a 3-wire Leveling, the mean reading for the backsights or foresights is computed as: sum of the…

A: To compute the determination of three wire reading from the following.

Q: Q2) In the figure shown, find the direction from point M into point P, if you know the direction the…

Q: For a highway curve, R will be rounded off to the nearest multıple of 10 m. Field measurements show…

Q: A loop traverse ABCDE with a bearing on course DE of S 71 degree 42 minutes 15 seconds E, and the…

A: Given: ∠A=60°53'30''∠B=215°58'00''∠C=65°10'10''∠D=110°∠E=86°58'00'' To find; Angular error and…

Q: 13. A horizontal distance measured at 687.40 m is to be established along a line that slopes at a…

Q: From the given differential leveling notes, compute the difference in elevation between stations 5…

Q: Example - : The bearings of a closed traverse ABCD are as under. Calculate ncluded angles and apply…

Q: 6. There is a signaling tower on the top of a hill. In order to determine the elevation of the tower…

Q: 1.283 BM-1 1.284 (а) 1.285 0.675 0.674 BM-2 0.677 (b) 0.674 0.677 0.678 Sum Mean INSTRUMENT SET UP…

Q: Reduce the set of differential leveling notes in Table 2-11, and perform the arithmetic check.…

Q: To use a level in the field, it is necessary to center the instrument over a known point before tilt…

A: It’s true and false based, statement based surveying question. Please refer below statement for…

Q: For the given line with equation 2x – 3y = 12, the slope and the y-intercept is Slope: 3/2;…

A: Write the given equation in slope - intercept form That is y= mx+c Here m= slope c =…

Q: The following are the observed bearings of a close traverse. Compute the error of interior angle and…

Q: Compute the slope at point C.

A: Use moment area method

Q: 1)Determine the slope and deflection at point “C” using Virtual work method E = 29000 ksi, A= 3500…

Q: The angles of a six-sided traverse are turned so that the 95% error of any angle is ±1.9". Part A…

A: For a traverse having a number of sides, Also, for error, the error in any angle, To determine the…

Q: Sta. B.S. Н. F.S. Elev. В.М.1 1.234 42.390 T.P.1 0.965 2.732 T.P.2 2.332 3.642 T.P.3 0.682 3.224…

Q: Helght of Torget Une of Slght Assume 90* Horlzontal Une Level Surface HJ. Level Surfoce G Mean Soo…

Q: hand written plz Horizontal Curve data STAPI= 98+47.30 R = 1000.00 A=19° 20'00" What is the…

Q: The combined correction for curvature and refraction can be given as:- A C = 16d²/6R B C skippe d D…

A: Given- Combined correction is the total of the curvature correction and refraction correction.

Q: y 5 kips/ft 6 ft FIGURE P7.45 9 kips/ft 2.5 m FIGURE P7.46 B 25 kN/m B 10 ft 4.0 m 11 ft 70 kN/mm C…

Q: Ifr=h(4h3 – 5), find the percentage error inr ath=1, if the error in h %3D is 0.04.

A: Equation, r = h( 4h5 - 5 ) h = 1 error in h = dh = .04

Q: 21 - If the distance between points A and B with a slope of 30% is 100 hm, how many decares is the…

Q: 4. The slope distance (L1) measured between A and B is 28.533m. Determined the correction necessary…

A: Correction = True value - Measured value In given question , Horizontal equivalent = true value…

Q: 15 kN/m Zoom image Bour 3 m 3m CH 20 kN 3 m D

Q: Find the hearing and sketch the graph of the traverse. scale used

A: Here first we draw the traverse to check the error. Here we see E is not meeting at A…

Q: The inclination distance was evaluated a distance of 300 meters using a tape measure in several…

A: segment length L Angle θ Difference in elevation b/w ends h=L×tanθ Slope correction for the…

Q: Two cross sections AB and CD each perpendicular to the base line AC of 250 m length are established…

Q: Q2/ A rectangular shape, its dimensions has been measured with tape, and it is found that the first…

A: area of rectangle = 67500m2 standard error = +/- 44.54 m2

Q: Given the data of an open traverse below, convert it into figure and determine its corresponding…

Q: In the case of angular measurements being more precise than linear measurements, the traverse can be…

A: The traverse can be balanced using angular measures if they are more accurate than linear…

Q: Q1/ find the area of the close traverse which is shown in the below figure by (60 degree) 1- DMD…

A: Solution: Given: A = 0,10 B = 4,23 C = 13,18 D = 9,1 F = 6,13

Q: The following are the observed bearings of a close traverse. Compute the error of interior angle,…

A: Given, To determine, corrected bearing of each line

Q: in meter were obtain center line of natural ground of a road. The elevation of de Line RL 148.4 m…

A: Rise and Fall method is used to find the level at each station Here the Road level at station 0+00…

Q: Using Virtual Work Method, determine the slope and defection at B and C.

Concept explainers

Traverse Survey

Traverse surveying is a popular method of surveying. Traversing is that type of survey where several connected survey lines form a framework and the directions and lengths of the survey lines are measured with the help of a tool to measure angles and tape or chain respectively. Traverse networks involve placing survey stations in a queue or trail and using pre-tested points as a basis for looking at the next point. This type of surveying is different from Tacheometric surveying, where only angles are measured and the process of chaining is reduced.

Question

Q5/ A differential leveling are began at B.M1 to B.M2 [in 4th degree
leveling process], determine the error of closure and maximum
acceptable error, then correct the elevation of all points if the error
are acceptable, use the data in the table below.
Point
B.M 1
A
T.P1
B
B.M2
Distance
(m)
....300..
****
****
150....
.... 280
****
R.L
31.257
31.801
30.773
29.624
30.259
Correction
Corrected
R.L
R.L (Fixed)
30.270

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1: Given data

VIEW

Step 2: Correction

VIEW

Step 3: Adjustment of RLs

VIEW

Step 4: Corrected RLs

VIEW

Solution

VIEW

Step by step

Solved in 5 steps with 6 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

Given the deflection angle of a 6-side closed traversed. Find the Bearings of each course and Sketch the traverse and show your solution.
The instrument used was a transit with an internal focusing telescope and a stadia interval factor of 99,Compute: a) DRAW DIAGRAMb) The Elevation at the turning point.c) The elevation at Point B.d) The gradient from A to B if all the stations are in a straight line.
Given the following deflection angles of a closed traverse. Assume bearing of line AB is S 40° E. DEFLECTION ANGLES 85°20' L 10°11'R STATION A B 83°32' L D 63°27' L 34°18' L 72°56' L 30°45' L E F G a) Compute the total error of the deflection angle. b) Compute the bearing of line DE. c) Compute the bearing of line GA.
Given the following differential notes for a three-wire leveling from BM1 to BM2, compute for the elevation at BM2 and solve for the horizontal distance between TP1 and TP2. Assume stadia interval factor equal to 100 and instrument constant equal to zero. STATION BS МEAN HI FS МEAN ELEVATION 5.27 BM1 3.97 54.38 2.67 3.27 3.81 ТР1 2.01 2.55 0.75 1.3 3.18 8.52 ТР2 1.88 7.16 0.58 5.81 2.91 8.5 ТРЗ 1.515 7.13 0.325 5.77 3.68 8.29 ТР4 2.56 6.92 1.43 5.56 7.81 6.67 ТР5 6.49 5.15 5.16 3.63 4.25 BM2 2.7 1.16 О а. 44.78/654 O b. 41.24/523 O c. 40.35/533 O d. 40.06/512
When performing a leveling process for the longitudinal section of a road, the following readings were recorded: The first reading was taken on the leveling number (B.M1), whose Tevel is (60 meters), while the rest of the points were taken on the section points (00+0. 0+50 + 00+ 1... . (While working, lift the device after the fourth, seventh, and tenth reading. Arrange the readings in a table, then complete the table and verify the correctness of the calculations. Draw the segmént and establish a slope line inclined by 0.4% - and its level at the beginning of the project is 60 meters. Find the burial depth in each station. " Reading sequence 1 2 3 4 5 6 7 8 9 10 11 12 13 Reading the ruler 1.35 1.72 1.98 2.05 2.17 2.76 2.98 0.67 1.78 2.48 |2.88 3.10 3.39|
H.W13/ The following offsets were taken from a chain line to a hedge: Distance (m)0 10 20 30 40 80 120 160 200 210 220 Offsets (m) 21 15 16 22 Compute the area between the chain line and the end offsets by: (a) Trapezoidal Rule. (b) Simpson's Rule.
Refer to the given table of differential leveling, find the value of A find the value of B (m) find the Value of C (m)
The two points 1 and 2 are spaced at a horizontal distance of 243.22 m. The elevation of point 1 is 911.46 m and that of point 2 is 903.37 m. Then, the gradient from point 1 to point 2 in percent % is : Finish attempt ... Jump to... Surveying Lecture 07-03-... 2.
An instrument is set-up at point M and vertical angles are observed at N (-21°15') and O (+33°45'). The height of instrument from point M is 1.5865m. The horizontal distance of NM and NO are 35G.2552m and 9GF.5565m respectively. If point O is at elevation 6AE.6453m, a. Determine the elevation of N neglecting the effects of curvature and refraction. b. Determine the elevation of N making due allowance for curvature and refraction.
Q3/ A survey line AB crosses a river. Line DF and CG are run perpendicular to the survey line having lengths of 100m and 200 m respectively. Another line FH is set at the right angle to DF such that point G lies on the survey line at the extension of EF and at a distance of 175m from F. Compute the distance AB. If the distances AC = 25m and EB= 75m. .B 75m LE D 100m 175m C 25m A F H 200m Tra G
Hi, can you please solve this again? The one I saw have some errors. Thank you so much!
The constant K and C for certain instrument were 99.81 and 0 respectively. The ground makes a uniform slope of 9.8% from point A to point B. With the instrument at A and staff at B, readings were taken but due to obstruction in the line of sight, only reading was recorded to be 1.99m if the vertical angle of the instrument was 6.49° and Height of instrument above A was 1.7m. Determine the horizontal distance between A and B.