4. Calculate the Elmore time constant from node A to node B of the following RC network. R₁ = R₂ = R3 = R₁ = R₁ = R₁ = R7 = Rg = 100, and C₁ C₂ C3 C4 C5 C6 C7 = Cg = 100fF. = = = = = = A R₁ C₁ H₁ R₂ R3 R4 C3 C₂ H•• H C4 R5, R₁ ww R1 H C6 TH.. C5 C7 Rg ww C8 B
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- Five capacitors, C1 = 3 pF, C2 = 7 pF, C3 = 2 pF, C4 = 4 pF, and C5 = 12 pF, are connected as shown in the circuit diagram below. The equivalent capacitance of the circuit is pF. Answer in picofarads (pF) and round your answer to have one digit after the decimal. C2 C3 C, C4 C5 12 volt Your Answer: AnswerA 22-k resistor and a 0.02-F capacitor are connected in series to a 5-V source. How long will it take the capacitor to charge to 3.4 V Select one: a. 0.501 ms b. 0.66 ms c. 0.44 ms d. 0.70 msA series R–L–C circuit comprises a 5µF capacitor, a 4ohm resistor and a variable inductance L. The supply voltage is 10∠0◦ V at a frequency of 159.1 Hz. The inductance is adjusted until the p.d. across the 4 ohm resistanceis a maximum. Determine for this condition (a) the value of inductance, (b) the p.d. across each component and (c) the Q-factor of the circuit.
- for the R-th part. isn't R3 and R5 in series not parrallel? If not, explain why. If so, fix the solution. THank you.Adpole having anomentp=3-5ŷ +lont nc m is located at Q(ir3)-4jinfveespa.ce Find uet pase)Find the voltage across and the charge on each capacitor in the following network. C₁ C3 300 pF 500 pF- QT = 18000 PC C2 C4 600 pF 500 pF-
- The figure below shows a simple RC circuit with a 3.30-μF capacitor, a 4.40-M resistor, a 9.00-V emf, and a switch. What are the following exactly 9.00 s after the switch is closed? (a) the charge on the capacitor 13.7204 UC (b) the current in the resistor 0.0110522 x Your response is off by a multiple of ten. HA (c) the rate at which the capacitor is storing energy μW (d) the rate at which the battery is delivering energy μWAttenuators with Capacitances Construct the circuit in Figure. Use R1 = 1kohm, C1-39nF. R2=3.9kohm. Vi C1 R1 HH R2 Vo What is the effect of the capacitor C1 in the circuit? You may use equations to help explain your answer.Draw a seven-segment display, show the number highlighted in figure 1 (d3 -d0 are the input, a -g are the outputs). III. Simulation Wavetorm Editor - Cers/Ahmad Fainuz/Desanop/DLD Lab Practice/bedseg - beaeg - bcaseg 2018o03121936sim.vwwt Ee ep Ea w smutation search altera.com Haster Time Bar: ops Pointer: s29 us Start End iterval 529 us o ps 0 ps २ 2.56 us S12 us 75 us 10.24 us 12 s 15.36 us 172 us value at Name Ops do Figure 1
- What does the following circuit schematic present? R4 Y_OUT D1 02 VCC LR1 R5 www LR3 LR8 VIN N D3 Ra 3 Learning Outcome 6 LRT 04 RE VEE a) Wave shaping circuit that converts a triangular voltage to sinusoidal. b) Schmitt trigger c) Wave shaping circuit that converts a square voltage to sinusoidal. d) Integrator hpCalibri (Body) -11 by AaBbCcDx AaBbCcD AaBbC AaBbCc AaB AaBbCc. mat Painter BIU 1Normal 1No Spaci. Heading 1 Heading 2 Title Subtitle Chang Styles d Font Paragraph Styles IMPEDANCE QUIZ # 2 1. What capacitance when connected in series with a 500Q resistor will limit the current drawn from a 48-mV 465-kHz source to 20µA? * a. 144pF b. 145pF c. 146pF d. 147pF MY ANSWER: c.146pF 2. What is the total impedance at 20kHz of a series circuit consisting of a 1.5mH inductance, a 100Q resistance, and a 0.08uF capacitance? * a. 1340 41.7 b. 1930 L-37.2" C. 920 290 d. 530 2-12.6°Original Schematic and OrCAD Schematic: The input primary voltage is 250V, frequency 50 Hz, primary inductance setting is 2000H and secondary inductance is 10H and voltage peak to peak ripple is approximately equal to 92mv. U1 D4 IN our DINA002 C3 DIN002 90u R1 R2 10k TXI BC540A V1 VOFF =0 VAMPL 2 FREQ- 50 AC0 XFRM_LINICT-SEC D5 DIN4002 C2 0.384m 84 5 HH