4. A student has prepared 0.05 M solution of CH3-C=CH and has added to it 0.05 M solution of potassium tert-butoxide (K* O-C(CH3)3). (iv) Calculate the percentage of deprotonated methyl acetylene taking into account that pKa of the conjugate acid of potassium tert-butoxide equals 18 and pKa of methyl acetylene equals 24.

Organic Chemistry
8th Edition
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Chapter18: Functional Derivatives Of Carboxylic Acids
Section: Chapter Questions
Problem 18.43P: The following sequence of steps converts (R)-2-octanol to (S)-2-octanol. Propose structural formulas...
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4.
A student has prepared 0.05 M solution of CH3-C=CH and has added to it 0.05 M solution of
potassium tert-butoxide (K" O-C(CH3)3).
(iv) Calculate the percentage of deprotonated methyl acetylene taking into account that pKa of
the conjugate acid of potassium tert-butoxide equals 18 and pKa of methyl acetylene equals 24.
Transcribed Image Text:4. A student has prepared 0.05 M solution of CH3-C=CH and has added to it 0.05 M solution of potassium tert-butoxide (K" O-C(CH3)3). (iv) Calculate the percentage of deprotonated methyl acetylene taking into account that pKa of the conjugate acid of potassium tert-butoxide equals 18 and pKa of methyl acetylene equals 24.
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