4) A strip footing is to be placed 2m below the surface of soil having a cohesion of 40kpa, unit weight of 18.2kn/cum and angle of friction of 10deg. Nc=9.61 Nq=2.69 Ny=0.56 Nc'=8.02 Nq'=1.94 Ny'=0.24 a) Assuming local shear failure, compute the ultimate bearing capcity of footing if width is 1.25m b) Considering a rectangular footing of 1.25mx6m and a load factor of 2.5,

4) A strip footing is to be placed 2m below the surface of soil having a cohesion of 40kpa, unit weight of 18.2kn/cum and angle of friction of 10deg. Nc=9.61 Nq=2.69 Ny=0.56 Nc'=8.02 Nq'=1.94 Ny'=0.24 a) Assuming local shear failure, compute the ultimate bearing capcity of footing if width is 1.25m b) Considering a rectangular footing of 1.25mx6m and a load factor of 2.5,

Principles of Geotechnical Engineering (MindTap Course List)

9th Edition

ISBN:9781305970939

Author:Braja M. Das, Khaled Sobhan

Publisher:Braja M. Das, Khaled Sobhan

Chapter16: Soil Bearing Capacity For Shallow Foundations

Section: Chapter Questions

Problem 16.5P: Redo Problem 16.1 using the modified general ultimate bearing capacity Eq. (16.31). 16.1 A...

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A 2.0 m 2.0 m square pad footing will be placed in a normally consolidated clay soil to carry a column load Q. The depth of the footing is 1.0 m. The soil parameters are: c = 0, =26, = 19 kN/m3, cu = 60 kN/m2 (=0 condition). Determine the maximum possible value for Q, considering short-term and long-term stability of the footing.
Redo Problem 16.1 using the modified general ultimate bearing capacity Eq. (16.31). 16.1 A continuous footing is shown in Figure 16.17. Using Terzaghis bearing capacity factors, determine the gross allowable load per unit area (qall) that the footing can carry. Assume general shear failure. Given: = 19 kN/m3, c = 31kN/m2, =28, Df = 1.5 m, B = 2 m, and factor of safety = 3.5. Figure 16.17
Redo Problem 16.2 using the modified general ultimate bearing capacity Eq. (16.31). 16.1 A continuous footing is shown in Figure 16.17. Using Terzaghis bearing capacity factors, determine the gross allowable load per unit area (qall) that the footing can carry. Assume general shear failure. Given: = 19 kN/m3, c = 31kN/m2, =28, Df = 1.5 m, B = 2 m, and factor of safety = 3.5. Figure 16.17 6.2 Refer to Problem 16.1. If a square footing with dimension 2 m 2 m is used instead of the wall footing, what would be the allowable bearing capacity?
A strip footing is to be placed 2m below the surface or soil having a cohesion of 40 KPa, unit weight of 18.2 KN/m', and angle of friction of 10 Nc = 9.61 N = 2.69 Ne = 8.02 N = 1.94 N, = 0.56 N,' = 0.24 a) Assuming local shear failure, compute the ultimate bearing capacity of the footing if the width is 1.25 m. Ans. 287.21 KPa b) Considering a rectangular footing of 1.25m x 6m and a load factor of 2.5, determine the allowable bearing capacity under general shear failure. cN. (1 + 0.3) + yD,N, + 0.5yBN, (1 – 0.25 Quit Ans. 204.97 KPa c) Find the allowable load that the rectangular footing could carry Ans. 1537.28 KN
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