A strip footing is to be placed 2m below the surface or soil having a cohesion of 40 KPa, unit weight of 18.2 KN/m', and angle of friction of 10° Ne = 8.02 N = 1.94 Nc = 9.61 N = 2.69 N, = 0.56 N,' = 0.24 a) Assuming local shear failure, compute the ultimate bearing capacity of the footing if the width is 1.25 m. Ans. 287.21 KPa b) Considering a rectangular footing of 1.25m x 6m and a load factor of 2.5, determine the allowable bearing capacity under general shear failure. B. Qut = cN: (1+ 03) +yD,Ng + 0.5YBN,(1 – 0.2 %3D Ans. 204.97 KPa c) Find the allowable load that the rectangular footing could carry Ans. 1537.28 KN

A continuous footing with a B = 7.5ft is constructed with a Df of 3ft in a soil with the following properties: c' = 210 lb/ft? Y = 115 lb/ft³ Ø' = 25° If bedrock exists 6ft below grade use equation 7.2 to determine the ultimate bearing capacity.

depth "z" = 16ft

Two footings, one circular and the other strip, are founded on the surface of a purely Cohesionless soil. Diameter of the circular footing and width of strip footing is same. Then, the ratio of ultimate bearing capacity of circular to strip footing is: