344614.2214230.qx3zqy7 2 def double_pennies (num_pennies, num_days): total_pennies - e 4 5 * Your solution goes here 6 7 else: total_pennies = double_pennies ( (num_pennies * 2), (num_days - 1)) 10 return total_pennies 11 12 # Program computes pennies if you have 1 penny today, 13 # 2 pennies ofter one day, 4 ofter two days, and so on 14 starting_pennies = int (input ()) 15 user_days = int (input ()) 16 17 print ('Number of pennies after', user_da ys, 'days: ', end="") 18 print (double_pennies (starting_pennies, user_days))

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Add an if branch to complete double_pennies()'s base case.
Sample output with inputs: 1 10
Number of pennies after 10 days: 1024
Note: If the submitted code has an infinite loop, the system will stop running the code after a few seconds, and report "Program
end never reached." The system doesn't print the test case that caused the reported message.
Transcribed Image Text:Add an if branch to complete double_pennies()'s base case. Sample output with inputs: 1 10 Number of pennies after 10 days: 1024 Note: If the submitted code has an infinite loop, the system will stop running the code after a few seconds, and report "Program end never reached." The system doesn't print the test case that caused the reported message.
344614.2214230.qx32qy7
2 def double_pennies (num_pennies, num_days) :
total_pennies
4
" Your solution goes here
...
6
7
else:
total_pennies
double_pennies ((num_pennies
2), (num_days - 1))
10
return total_pennies
11
12 # Program computes pennies if you have 1 penny today,
13 # 2 pennies after one day, 4 after two days, and so on
14 starting_pennies
15 user_da ys
int(input ())
!!
int (input ())
16
17 print('Number of pennies after', user_days, 'days: ', end="")
18 print(double_pennies (starting_pennies, user_days))
Transcribed Image Text:344614.2214230.qx32qy7 2 def double_pennies (num_pennies, num_days) : total_pennies 4 " Your solution goes here ... 6 7 else: total_pennies double_pennies ((num_pennies 2), (num_days - 1)) 10 return total_pennies 11 12 # Program computes pennies if you have 1 penny today, 13 # 2 pennies after one day, 4 after two days, and so on 14 starting_pennies 15 user_da ys int(input ()) !! int (input ()) 16 17 print('Number of pennies after', user_days, 'days: ', end="") 18 print(double_pennies (starting_pennies, user_days))
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