Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN: 9780133594140
Author: James Kurose, Keith Ross
Publisher: PEARSON
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Please take screenshots of the program
![**Section 3.2**
**3.1 (Algebra: solve quadratic equations)**
The two roots of a quadratic equation \( ax^2 + bx + c = 0 \) can be obtained using the following formula:
\[
r_1 = \frac{-b + \sqrt{b^2 - 4ac}}{2a} \quad \text{and} \quad r_2 = \frac{-b - \sqrt{b^2 - 4ac}}{2a}
\]
\( b^2 - 4ac \) is called the discriminant of the quadratic equation. If it is positive, the equation has two real roots. If it is zero, the equation has one root. If it is negative, the equation has no real roots.
Write a program that prompts the user to enter values for \( a \), \( b \), and \( c \) and displays the result based on the discriminant. If the discriminant is positive, display two roots. If the discriminant is 0, display one root. Otherwise, display “The equation has no real roots”.
Note that you can use Math.pow(x, 0.5) to compute \( \sqrt{x} \). Here are some sample runs.](https://content.bartleby.com/qna-images/question/8dbcbf0b-9123-4a1c-9796-89fa34227664/cdfe39b0-8e80-4ecc-898f-ab5c4d06a8e8/34ylayf_processed.jpeg)
Transcribed Image Text:**Section 3.2**
**3.1 (Algebra: solve quadratic equations)**
The two roots of a quadratic equation \( ax^2 + bx + c = 0 \) can be obtained using the following formula:
\[
r_1 = \frac{-b + \sqrt{b^2 - 4ac}}{2a} \quad \text{and} \quad r_2 = \frac{-b - \sqrt{b^2 - 4ac}}{2a}
\]
\( b^2 - 4ac \) is called the discriminant of the quadratic equation. If it is positive, the equation has two real roots. If it is zero, the equation has one root. If it is negative, the equation has no real roots.
Write a program that prompts the user to enter values for \( a \), \( b \), and \( c \) and displays the result based on the discriminant. If the discriminant is positive, display two roots. If the discriminant is 0, display one root. Otherwise, display “The equation has no real roots”.
Note that you can use Math.pow(x, 0.5) to compute \( \sqrt{x} \). Here are some sample runs.
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