3. The graph below shows the displacement vs time of a student leaving the NSCI 110after physics class walking towards the cafeteria for lunch (assume a 1-D motion) Atsome point between NSCI 110 and the cafeteria, the student realizes they have lefttheir cell phone in the classroom, so they turn back to get it.Displacement vs Time120100nol Velocity vs Time801.5604030609012015018021020-1.5306090120150180210Time (s)a. How far did the student walk before realizing that they left their cell phone in theclassroom? How long did this take? (2 marks)b. With what velocity did the student walk back to the classroom? (2 marks)c. Fill out the velocity vs time graph above. (2 marks)Distance (m)

Answered: 3. The graph below shows the…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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The velocity of a particle which moves along the x axis is given by v = 2- 4t +5 tz, where t is in seconds and v is ft/s. The particle is at the position x, = 3ft when t -0. Find the ffg: 1. position when t = 3sec 2. Acceleration when t = 3sec
1.A conductor in a train travelling at 4.0 m/s (N) walks across the train at 1.2 m/s (E) to validate a ticket. If the trian car is 4.0m wide, how long does it take the conductor to reach the other side? vog=? vom 1.2 m/s(E) (1.2/4.2) vmg= 4.0 m/s(N) vog 4.2m/s(N17E) Ad At = Δυ At = 3.3s vom=5m/s(W) vmg=11m/s(S = 12m/s = vog vom+vmg -5m/s (W)+ 11m/s(S) = sqrt (5m/s)^2+ (1m/s)^2 sin 90 12m/s 4.0m/s 1.2m/s 2. A jetski speeds across a river at 11 m/s relative to the water. The jet ski's heading is South. The river is flowing West at 5m/s. Determine the jet ski's velocity relative to the shore. vog=? = vog vom+vmg sin 0 5m/s = 1.2m/s(E) + 4.0m/s(N) =sqrt (1.2m/s)^2 + (4.0m/s)^2 =4.2 m/s = 24° Therefore the answer is 12m/s (S24W) Tan-1= = 17
3. A bee flies in a straight line (a "beeline" as they say). The initial speed of the bee is Vo = 100 cm/s. The acceleration of the bee versus position is given by the graph below. a [cm/s²] 500 0 -250 50 105 145 195 s [cm] a. At what position will the speed of the bee be maximum? Hint: it will be one of the labeled points: 0cm, 50cm, 105cm, 145cm or 195cm. b. What is the speed of the bee at that location? C. What is the speed of the bee after traveling the full 195cm? Hints: you don't need to figure the equations for the four lines to do the integrals, and be careful of the signs.
2. A spaceship in a videogame is programmed to move following the quantities below where velocity v is in m/s, time t is in seconds, and position vector r is in meters. The spaceship moves at constant acceleration in both axes. The spaceship starts moving from the position (5,-3). f (2t + 5)i + (t- 3)j V = 2ti + (2 + t)j (a) At what position will the spaceship be after 3.5 seconds. (Ans: (17, -2.5)) (b) What will be the velocity of the spaceship at moment it reaches 18.0 m in the x-axis? Express the answer in unit-vector form. (Ans: V = 81 + 4j) %3D
SITUATION 2. The motion of a particle in rectilinear motion is defined by the relation x = t³ - 8t² + 16t - 5, where x and t are expressed in meters and seconds respectively. Determine the following: a. The time when the velocity is zero. b. The position and acceleration at those instants of time when the velocity is zero. c. The position, displacement, and the total distance travelled when the acceleration is zero.
1. Particle Under Constant Acceleration
The position of a particle as it moves horizontally is described by s(t) = 2sint+sin 21. If 's' is the displacement in metres and 't' is the time in seconds, where 0srs6: a) 2. Determine the velocity of the particle when t = 3sec. -0.06 b) When is the particle moving in the positive direction? When is the particle speeding up? 1E[0,1)U(5.24,6] c) te (1.047,1.823)U(3.14,4.46)U (5.23,6)
1. Suppose that the velocity of a particle in motion is given by v(t) = 44t² +²+1 feet per second, where t is in seconds from now. Find the position of the particle after 5 seconds.
Can I please get some help with this problem. I can't seem to figure this out. thank you!
5. For the following scenarios, you should mark a reference point on the object. Calculate the distance and displacement travelled by the flying device in each of the three flights. Show your work and include the units. Flight 1 P 10 Flight 2 0 10 Flight 3 H 20 20 10 30 30 10 40 cm 20 50 50 60 60 cm 40 70 70 80 X₂ 80 50 60 90 100 90 n 70 100
The position of an object moving in one dimension is given by the equation: x = 18t - 2t + 4 %3D 1. Are there any points in time when the object will be not in motion? (i.e. when its velocity is zero) 2. What are the position, speed and acceleration of this object at t=5s.

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