3. Given the following thermochemical equations. 2 Hzle) + Ozle) ----→ 2 H20 (1) N2Osle) + H2O (1) --→ 2 HNO3 (1) % N2 (e) + 3/2 O2 (e) + % Hzl«) --→ HNO3{) AH° = - 571.5 kJ AH° = -76.6 kJ AH° = -174.0 kJ Calculate the AH for the reaction: 2 Nz(8) + 5 Oz(8) → 2 N2Os(e) -

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3. Given the following thermochemical equations.
2 H2(8) + Ozle) ---→ 2 H2O (1)
N2Osle) + H20 (1) ----→ 2 HNO3 (1)
% N2 (e) + 3/2 O2 (e) + ½ H2(g) ---→ HNO31)
AH° = - 571.5 kJ
AH° = -76.6 kJ
AH° = -174.0 kJ
Calculate the AH° for the reaction:
2 Nz(g) + 5 Ozle)
→ 2 N¿Os(8)
Transcribed Image Text:3. Given the following thermochemical equations. 2 H2(8) + Ozle) ---→ 2 H2O (1) N2Osle) + H20 (1) ----→ 2 HNO3 (1) % N2 (e) + 3/2 O2 (e) + ½ H2(g) ---→ HNO31) AH° = - 571.5 kJ AH° = -76.6 kJ AH° = -174.0 kJ Calculate the AH° for the reaction: 2 Nz(g) + 5 Ozle) → 2 N¿Os(8)
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