3. Given the data 0×123456789ABC and the starting location (lowest address) of data memory (0x018) to store this data in an 8-bit MCU, please show the memory maps for both endian systems.

Question 4 Why must the single-cycle datapath have separate instruction and data memories? The formats of data and instructions are different in RISC-V, and hence different memories are needed. It is less expensive to have separate memories. The processor operates in one cycle and cannot use a (single-ported) memory for two different accesses within that cycle. All of the above.

In this setup, data for each instruction is obtained independently of how data for other instructions is obtained. When we need a(n): A Instructions/Data Sets That Vary B A Variety of Information and Directions in a C Format Exclusive Information Straight D Incident Several Insts From a Single Infusion

A computer system contains a big endian byte addressable memory system with 8 separate memory modules. Each memory module is 32 bits wide and contains 134217728 cells. Cells within each memory module are numbered 0 through 134217727. a) If the memory employs high order interleaving, what is the 32-bit memory address of cell 1048578 within module 3? b) If the high order interleaved memory uses little-endian instead of big-endian storage order, what is the 32-bit memory address of cell 511 within module 1? c) If the memory employs low order interleaving, what is the 32-bit memory address of byte 1048575 within module 2? Bytes are numbered starting from 0. Express the address in hex. d) What is the main advantage of using low-order interleaved memory compared to using high-order interleaved memory?