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3. For the following plant 0.125 G(s) = (s+0.750)(8 +0.500) (s+0.250) under a unitary closed loop with a controller Ge(s): (a) Determine the value of Ke> 0 and its associated w such that s = jw is a closed loop pole if Ge(s) = Ke.

3. For the following plant 0.125 G(s) = (s+0.750)(8 +0.500) (s+0.250) under a unitary closed loop with a controller Ge(s): (a) Determine the value of Ke> 0 and its associated w such that s = jw is a closed loop pole if Ge(s) = Ke.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Answers are a) w= 0.829 and Ke 7.5 b) G.(s)= (4.263s²+4.5s+1.188)/s Please explain... fastly
3. For the following plant 0.125 G(s) = = (s +0.750) (s+0.500) (s +0.250) under a unitary closed loop with a controller Ge(s): (a) Determine the value of Ke > 0 and its associated w such that s = jw is a closed loop pole if Ge(s) = Ke.
Transcribed Image Text:3. For the following plant 0.125 G(s) = = (s +0.750) (s+0.500) (s +0.250) under a unitary closed loop with a controller Ge(s): (a) Determine the value of Ke > 0 and its associated w such that s = jw is a closed loop pole if Ge(s) = Ke.
(b) Design a PID controller using the periodic oscillation method such that ess=1 = 0.
Transcribed Image Text:(b) Design a PID controller using the periodic oscillation method such that ess=1 = 0.
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