V1- Node a R1 4 K₂ www R₂ R3 www Ra www a) Determine the equivalent resistance, in kQ2, of the circuit. []
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![Given V1=32.5 Volt,
R1=117.5 KQ, R2-80 kn, R3-85 kn, R4=15 kQ.
V1
Node a
RT
L
R₁
M
R₂
www
R3
www
Ra
www
a) Determine the equivalent resistance, RT
in ko, of the circuit. [ ]
b) Find current I in mA.
c) Use the current divider rule to
determine the current in resistor R1 in
mA. E
d) Use the current divider rule to
determine the current in resistor R2 in
mA. [C
e) Use the current divider rule to
determine the current in resistor R3 in
mA. D
f) Use the current divider rule to determine
the current in resistor R4 in mA. L
g) Verify Kirchhoff's current law at node
a.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8c9f0476-6c85-451b-8a0c-4e1b26b8596e%2Fa2fc50d8-8f83-4b48-b78a-bdb205c06ab5%2F1ogc5q_processed.jpeg&w=3840&q=75)
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- dhjdhjhdjdhjfhfjdbfejfheidadadisfdfodf,fdhjfhdfj The equivalent resistance of three resistors A, B and C connected in parallel is 1.5 ohms. If A is thrice of B and C is 1/4 of B. Find the equivalent resistance when the three of them are connected in series? dhsfhfeirwdiwudwiwuiThe diagram in the figure shows a simple circuit consisting of a battery and a load consisting of two resistors.The battery voltage is UB = 56 V and the value of the resistors is:R1 = 1800R2 = 5400a) The ammeters in the circuit show the following value:A1 shows valueA2 shows valueA3 shows valueb) In the load, the effect developsc) The total resistance of the load isEstimate voltage E2 when E1=90sin2400t V, R1=R2=20 ohms, L1= L2=3mH and M=0.15mH
- Please help me solve for the total resistance, total current, and individual voltage if: VT = 30 VR1 = 7 ohmsR2 = 10 ohmsR3 = 6 ohmsR4 = 4 ohmsR5 = 8 ohmsR6 = 9 ohmsR7 = 5 ohmsR8 = 12 ohmsR9 = 3 ohmsR10 = 8 ohmsis made from a combination of A mixed resistors circuit as shown in Figure parallel and series circuits. The values of the resistances mentioned in the circuit are in Ohm (2) and the supply voltage is in Volt (V). Determine the: (i) Current through the circuit (I). (ii) Voltage drop (V) across the circuit. 0.6 0 4 0 0.5 0150 100 + VA- a -4V AVA -7V 81. B b Figure 2 shows a simplified model of a gas-discharge lamp. One characteristic of these lamps is that they exhibit negative resistance; in other words, as current increases the voltage drops further, making such lamps inherently unstable. As such, a current-limiting ballast is required. For the connection shown in the figure: 1. Find the equivalent Thevenin circuit of the lamp. 2. Find the ballast resistance needed to limit the current drawn from a 24-volt source to 6 amperes.
- For the circuit shown ,IC2 = 1mA ,VCE1 = 2V , and VCE2 = 8V 1. The value of RC is equal to ohm 2. The value of R1 is equal to ohm 3. The value of R2 is equal to ohmFor the circuit below, determine the resistor voltage. The source is 5 volts, the Zener potential is 5.2 volts and the resistor is 1k ohms.Three resistors of 50 N, 100 N and an unknown resistance R are connected in parallel and the combination is connected to a 25 V source. If the total current delivered by the source is 1 A, determine the following: A. The value of R (Ans. R = 100 2) B. The current in each resistor (Ans. I1 = 0.5 A, I2 = I3 = 0.25 A) C. Which resistor dissipates the highest power? Show your solution. (Ans. R1)
- shfdjkfdrhnacoioeniodinopidopdnieocmixoxwmipdf.ziudSALIDUDetu The equivalent resistance of three resistors A, B and C connected in parallel is 1.5 ohms. If A is thrice of B and C is 1/4 of B. Find the equivalent resistance when the three of them are connected in series? dhffrriru9eeQ2. I- For the voltage divider circuit below, (R1 = R2 = R3 = 10 kN, R4 = R5 =1 kn, Vi = 15V), (ZD1 & ZD2 are Zener diodes, zener voltage = 5.6 V) LED 1 and LED 2 are light emitting diodes R1 R2 R3 Vi ZD1 ZD2 LED1 LED2 R4 R5 I. What is the status of each LED (ON or OFF), LED1 ---- ON ----- LED 2 ----- OFE II. What is the current in R4 5 x 10-3 --. III. What is the purpose of resistors R4 and R5, ------ current limiter ----In the circuit shown below, if R1=5 ohm, R2=10 ohm and Vin = 2V. Then the current (I) will equal to: Vino Vout R1 R2 O a. -0.6A O b. 0.4A O c. -0.2A O d. -0.4A Oe. 0.6A